从bash输出中提取字符串

Question

我想提取查询给出结果的服务器。从下面的输出中，我必须提取服务器名称'TSMPDC1'

ANR1687I Output for command 'QUERY NODE pdviateng017' issued against server CSNDCTSMP008 follows:
ANR2034E QUERY NODE: No match found using this criteria.
ANR1687I Output for command 'QUERY NODE pdviateng017' issued against server TSMNDC18 follows:
ANR2034E QUERY NODE: No match found using this criteria.
ANR1687I Output for command 'QUERY NODE pdviateng017' issued against server TSMPDC1 follows:
Node Name                     Platform     Policy Domain      Days Sinc-     Days Sinc-     Locked?
Name                  e Last      e Passwor-     
Access          d Set     
-------------------------     --------     --------------     ----------     ----------     -------
XXXXXXXXXXXX                  Linux        DM_DECOMM                  <1             67       No   
x86-64                                                              
ANR1687I Output for command 'QUERY NODE pdviateng017' issued against server TSMIDC7 follows:
ANR2034E QUERY NODE: No match found using this criteria.

我尝试使用以下命令:

my_command | awk '/ANR1687I/{f=1} /Node Name/{f=0} f' | awk '/server/{f=1} /follows/{f=0} f'

但是输出是空的。

Answer 1

简化的awk:

awk '$1=="ANR1687I" && $NF=="follows:" {s=$(NF-1)} /Node Name/ {print s; exit}' file
TSMPDC1

解释:

awk '
if $1 is "VANR1687I and last field i.e. $NF is "follows:"
$1=="ANR1687I" && $NF=="follows:" {
s = $(NF-1)  # set variable s to value in last-1 field i.e. $(NF-1)
}
/Node Name/ {   # if line has text "Node Name"
print s      # print variable s
exit         # exit awk command
}' file