如何改变任何位

Question

我有一个被翻译成5位形式的文本。如何替换一些位，然后用改变的位输出文本?这里我的文本Hello输出01000 00101 01100 01100 01111有必要用相反的位替换任何位，然后以位形式输入我们更改的文本

这段代码

#include <iostream>
#include <string>
#include <bitset>
 
std::string toBinary(std::string const &str) {
    std::string binary = "";
    for (char const &c: str) {
        binary += std::bitset<5>(c).to_string() + ' ';
    }
    return binary;
}
 
int main()
{
    std::string str = "Hello world";
 
    std::string binary = toBinary(str);
    std::cout << binary << std::endl;
    
   
 
    return 0;
}

Answer 1

#include <iostream>
#include <string>
#include <bitset>
#include <vector>
std::string toString(std::string binary1)
{
    // use an array to store each letter's representation separately
    std::vector<std::string> arr;
    int i = 0;
    while (i < binary1.length())
    {
        std::string x = "";
        while (binary1[i] != ' ')
        {
            x += binary1[i];
            i++;
        }
        arr.push_back(x);
        i++;
    }
    // convert the bits back to string
    std::string binary2 = "";
    for (int i = 0; i < arr.size(); i++)
    {
        if (arr[i] == "00000")
        {
            binary2 += " ";
        }
        else
            binary2 += char(std::bitset<5>(arr[i]).to_ulong() + 64);
    }
    return binary2;
}
std::string toBinary(std::string const &str)
{
    std::string binary = "";
    for (char const &c : str)
    {
        binary += std::bitset<5>(c).to_string() + ' ';
    }
    return binary;
}
int main()
{
    std::string str = "Hello world";
    std::string binary1 = toBinary(str);
    std::cout << binary1 << std::endl;
    // change certain bits
    // for instance, we're changing the first bit and the 9th bit;
    std::string str1, str2;
    str1 = str2 = binary1;
    str1[0] = '1';
    str2[9] = '1';
    std::cout << toString(str1) << std::endl;
    std::cout << toString(str2) << std::endl;
    return 0;
}

输出:

01000 00101 01100 01100 01111 00000 10111 01111 10010 01100 00100 
XELLO WORLD
HGLLO WORLD