如何浏览字符串列并将任意整数转换为Python中的单词?

Question

我正在创建一个将通过字符串列的函数。有些字符串中有数字，有些字符串中没有数字。如果一个字符串包含一个数字，我想将该数字更改为文本版本(即'I was on hold for 20分钟'到'I was on hold for 20分钟')

这是我到目前为止所做的，但我认为isdigit()正在查看整个字符串，而不是字符串中的令牌。

import inflect
def int_to_word(words):
p = inflect.engine()
new_words = []
for word in words:
if word.isdigit():
new_word = p.number_to_words(word)
new_words.append(new_word)
else:
new_words.append(word)
return new_words

Answer 1

这完全取决于您传递给int_to_words的输入，而您的问题中没有包含这些输入。

---

输入:string

您需要将字符串拆分为一个列表，该列表由空格分隔。这样可以确保遍历整个数字，而不是字符串中的单个字符。

def int_to_word(words):
p = inflect.engine()
new_words = []
for word in words.split():
if word.isdigit():
new_words.append(p.number_to_words(word))
else:
new_words.append(word)
return ' '.join(new_words)
print(int_to_word('I was on hold for 20 minutes'))
#I was on hold for twenty minutes

---

Input:list

对于一个句子列表，您将需要添加一个额外的迭代。

def int_to_word(words):
p = inflect.engine()
result = []
for element in words:
new_words = []
for word in element.split():
if word.isdigit():
new_words.append(p.number_to_words(word)
)
else:
new_words.append(word)
result.append(' '.join(new_words))
return result

print(int_to_word(['I was on hold for 20 minutes', '1 2 3']))
#['I was on hold for twenty minutes', 'one two three']