C语言，更改字符变量

Question

int main()            
{  
charactername="tom";        
characterage=78;       
printf("his name is %sn", charactername);        
printf("his age is %dn", characterage);         
characterage=78;
charactername="John";
printf("his name changed to %sn", charactername);
printf("his age changed to %dn", characterage);

return 0;
}

当我在代码之间更改字符名时，代码不会运行，而如果我只更改年龄，代码会完美运行，为什么我不能更改字符变量，但我可以更改字符年龄？？(c语言(

Answer 1

两件事：

1. 您必须定义变量的类型
2. 无法分配数组

在您的代码中，您需要进行一些更改(在下面的注释中标记(

#include <stdio.h>
#include <string.h>
// header files are needed
#define ARRSIZ 64                               // choose any size you like 
int main(void)                                  // proper signature
{  
char charactername[ARRSIZ]="tom";        //define a char array and initialize it.
int characterage=78;                     // type is a must
printf("his name is %sn", charactername);        
printf("his age is %dn", characterage);         
characterage=78;                           // this is fine, only assignment
strcpy(charactername,"John");              // use strcpy to copy to an array
printf("his name changed to %sn", charactername);
printf("his age changed to %dn", characterage);

return 0;
}