如何从if-in-for循环中获得正确的输出

Question

a=  ['Emre', 'Hacettepe', 'University', 'Computer', 'Engineering']
b=  ['Kerem', 'METU', 'Architecture']
c=  ['Leyla', 'Ankara', 'University', 'Physics']
d=  ['Sami', 'Bilkent', 'University', 'Civil', 'Engineering'] 

#S=我作为参数编写的输入列表，但我没有在这里添加所有代码，因为它太长了。Etc输入：Emre,Ahmet

x=len(S)
for i in range(0,x):
list=[]
if a[0]== S[i] :
print('Name: '+ (a[0])+', University: '+a[1]+' '+a[2]+','+a[3]+' '+a[4],end=' ')
list.append(S[i])
if h[0]== S[i]:
print('Name: '+ (h[0])+', University: '+h[1]+' '+h[2]+','+h[3]+' '+h[4],end=' ')
list.append(S[i])
if e[0]==S[0]:
print('Name: '+e[0]+', University: '+e[1]+','+e[2],end=' ')
list.append(S[i])
if f[0]==S[i]:
print('Name: '+f[0]+', University: '+f[1]+' '+f[2]+','+f[3],end=' ')
list.append(S[i])
if a[0] or h[0] or e[0] or f[0]!= S[i] and S[i] not in list:
print('No record of '+"'"+S[i]+"'"+' was found!',end=' ')

在最后一个"if"语句中，我只想写不存在的语句，但我收到了错误的输出。

Name: Emre, University: Hacettepe University,Computer Engineering No record of 'Emre' was found! No record of 'Ahmet' was found!

输出中不应出现"Emre"的任何记录。我的错误在哪里？

Answer 1

您的逻辑错误。

if a[0] or h[0] or e[0] or f[0]!= S[i] and S[i] not in list:
print('No record of '+"'"+S[i]+"'"+' was found!',end=' ')

应该是

if a[0] != S[i] and h[0] != S[i] and e[0] != S[i] and f[0] != S[i] and S[i] not in list:
print('No record of '+"'"+S[i]+"'"+' was found!',end=' ')

更清晰的方法是

if S[i] not in [a[0],b[0],c[0],d[0]]:
print('No record of '+"'"+S[i]+"'"+' was found!',end=' ')

(注意，如果S[i]不在a-d中，它将永远不会在list中(

更好的方法是

students = {}
students['Emre'] = {'University':'Hacettepe', 'Course': 'Computer Engineering'}
students['Kerem'] =  {'University':'METU', 'Course': 'Architecture'}
for name in students:
print(name,students[name]['University'],", University, ",students[name]['Course'])