从字典列表中获取列数据

Question

我有以下数据:

locations = [
{"id": 1,"Name": "Ottawa"},
{"id": 2,"Name": "Ahmedabad"},
{"id": 3,"Name": "London"}
]

，我试图得到一个输出，其中显示的名称列表，所以:

[Ottawa, Ahmedabad, London]

或者类似的东西。我该怎么做，或者这有可能吗?

我已经创建了一个函数，可以给出单个名称

def find_names(Name):
try:
return ( location['Name'] for location in locations if location['Name'] == Name)
except:
raise BadRequest(f"Can't find the location by name {Name}")

，在查看特定路由时给出"Ottawa"的输出。

Answer 1

您的函数筛选某些名称。删除它，它应该可以工作

# use a list comprehension
[d['Name'] for d in locations]
# ['Ottawa', 'Ahmedabad', 'London']

另一种方法是调用operator.itemgetter

from operator import itemgetter
print(*map(itemgetter('Name'), locations))
# Ottawa Ahmedabad London