比较字符串与bash中的字符串列表

Question

我试图将服务与可用服务名称列表进行比较，如果在列表中找到服务，则更新服务，否则部署服务。但是在列表变量中服务可用的情况下只部署新服务呢?

SERVNAME=ner
SERVICE=$(az ml service list -g $(ml_rg) --workspace-name $(ml_ws) --model-name $(model_name) --query "[].name")
if [[ "$SERVNAME" == "$SERVICE" ]];
then
echo "Service Found: $(SERVNAME) and updating the service"
az ml service update --name $(AKS_DEPLOYMENT_NAME) 
--model '$(MODEL_NAME):$(MODEL_VERSION)' 
--dc aksDeploymentConfig.json 
--ic inferenceConfig.json 
-e $(ml_env_name) --ev $(ml_env_version) 
-g $(ml_rg) --workspace-name $(ml_ws) -v ;
else
echo "Service Not found and starting deploying new service"
az ml model deploy --name $(AKS_DEPLOYMENT_NAME) --model 
'$(MODEL_NAME):$(MODEL_VERSION)' 
--compute-target $(ml_aks_name) 
--ic inferenceConfig.json 
-e $(ml_env_name) --ev $(ml_env_version) 
--dc aksDeploymentConfig.json 
-g $(ml_rg) --workspace-name $(ml_ws) 
--overwrite -v ;
fi

示例列表

SERVNAME="ner"
SERVICE=[ "ner", "aks-gpu-ner-0306210907", "aks-gpu-ner-30012231", "aks-gpu-ner-1305211336"]

Answer 1

假设az ml命令返回json数组字符串，并且您希望检查如果数组包含变量SERVNAME的价值,你会请尝试:

SERVNAME="ner"
SERVICE='[ "ner", "aks-gpu-ner-0306210907", "aks-gpu-ner-30012231", "aks-gpu-ner-1305211336"]'
if [[ $SERVICE =~ ""$SERVNAME"" ]]; then
echo "Service Found"
# put your command here to update the service
else
echo "Service Not Found"
# put your command here to deploy new service
fi

正则表达式$SERVICE =~ ""$SERVNAME""匹配字符串$SERVICE包含用双引号括起来的子字符串$SERVNAME。

如果jq可用，您还可以说:

result=$(echo "$SERVICE" | jq --arg var "$SERVNAME" '. | index($var)')
if [[ $result != "null" ]]; then
echo "Service Found"
else
echo "Service Not Found"
fi

Answer 2

Bash没有列表，只有数组。

检查数组是否包含值，使用如下命令:

SERVNAME="ner"
SERVICE=("ner" "aks-gpu-ner-0306210907" "aks-gpu-ner-30012231" "aks-gpu-ner-1305211336")
if [[ " ${SERVICE[*]} " =~ " ${SERVNAME} " ]]; then
echo "Match Found For Service: $SERVNAME"
else
echo "Match Not Found For Service: $SERVNAME"
fi