替换为空的值(ZAPIER - Javascript)

Question

我想从URL中提取3个utm (utm_source, utm_medium, utm_campaign)，并将它们发送到zapier中的这个javascript代码步骤的下一步。

javascript代码运行完美:

let url = inputData.URL;

let queryString = url.split("?").pop();
let urlParams = new URLSearchParams(queryString);
let utm_source = urlParams.get('utm_source')
let utm_campaign = urlParams.get('utm_campaign')
let utm_medium = urlParams.get('utm_medium')
let utm_term = urlParams.get('utm_term')
let utm_content = urlParams.get('utm_content')

output = [{url, queryString, utm_source, utm_campaign, utm_medium, utm_term, utm_content}];

当URL没有UTM时，问题就出现了。在本例中，该值为空，因此我想用默认值(例如"organic")

替换它。

---

我开始尝试这样做，但它不工作:

if(utm_campaign === null || typeof utm_campaign === "undefined" || utm_campaign === "") {
utm_campaign = "ORGANIC";
}

请，谁能帮我这个javascript代码?提前谢谢你

Answer 1

这是使用ternary运算符的绝佳机会:

let url = inputData.URL;

let queryString = url.split("?").pop();
let urlParams = new URLSearchParams(queryString);
let utm_source = urlParams.get('utm_source') ? urlParams.get('utm_source') : 'definitely not organic'
let utm_campaign = urlParams.get('utm_campaign')
let utm_medium = urlParams.get('utm_medium') ? urlParams.get('utm_medium') : 'organic'
let utm_term = urlParams.get('utm_term')
let utm_content = urlParams.get('utm_content')

output = [{url, queryString, utm_source, utm_campaign, utm_medium, utm_term, utm_content}];

在这种情况下，您可以选择默认的per变量。