为什么'@'和'.'在'heykidhellogmail.com'返回 True？

Question

你好，我试着做一个电子邮件解析器，但它的行为很奇怪，谁能告诉我为什么

def parser(wrds):
s = set()
for wrd in wrds:
splited_wrd = wrd.split(' ')
for i in range(len(splited_wrd)):
wrds_indexed = splited_wrd[i]
if ('@' and '.' in wrds_indexed) and (len(wrds_indexed) > 13):
s.add(wrds_indexed)
yield from s

x = '[e-mail]', 'heykidgmail.com', 'heykidhello@gmailcom','[e-mail]'
print(list(parser(x)))

输出:

['heykidgmail.com', '[e-mail]']                                                                                                                                            
>>> 

谁能告诉我为什么heykidgmail.com在列表中，而它显然没有"@">

>>> '@' and '.' in 'heykidgmail.com'                                                                                                                                                    
True

当我在控制台中运行它时，为什么当@不在单词中时它显示为True ?

Answer 1

'@' and '.' in 'heykidgmail.com'

并不像你想象的那样。

被解释为

bool('@')  and  bool('.' in 'heykidgmail.com')

或

True  and  bool('.' in 'heykidgmail.com')

因此,

bool('.' in 'heykidgmail.com')

---

您需要独立测试两个:

s = 'heykidgmail.com'
'@' in s and '.' in s