在一个页面中使用一个按钮进行Ajax状态更新

Question

我试图更新我的订单状态在同一页面上，它是用ajax HTML显示的。

显示工作只是很好，但我想设置状态下一个只有一个点击，所以我想使用ajax为它太。

我的ajax PUT下一个状态

$(function () {
$(document).on('click', 'button#order_update', function (e) {
e.preventDefault();
let newStatus = '';
if ($(this).data('status') == 'pending') {
newStatus = 'confirm';
} else if ($(this).data('status') == 'confirm') {
newStatus = 'processing';
} else if ($(this).data('status') == 'processing') {
newStatus = 'picked';
}
let formStatusData = new FormData();
formStatusData.append('order_id', $(this).data('order'));
$.ajax({
type: 'PUT',
url: '{{ route("update-order-status") }}',
data: formStatusData,
success: (response) => {
console.log(response);
$(this).data('status', newStatus);
$(this).text(newStatus.charAt(0).toUpperCase() + ' order');
}
});
});
});

My ajax for html

$.ajax({
type: 'GET',
url: '/order/view/all',
dataType: 'json',
cache: false,
success:function(response){
$('#pimage').attr('url','/'+response.product.product_thambnail);
var product_name = $('#pname').text();
var id = $('#product_id').val();
var quantity = $('#qty').val();
var OrderView = ""
$.each(response.orders, function (key,value){
var productsList = '';
$.each(value.product, function (key,value) {
productsList += `
<div class="row gx-4">
<div class="col-lg-3">
<div class="pos-task-product">
<div class="pos-task-product-img">
<div class="cover" style="background-image: url(${value.product_thambnail});"></div>
</div>
<div class="pos-task-product-info">
<div class="flex-1">
<div class="d-flex mb-2">
<div class="h5 mb-0 flex-1">${value.product_name_en}</div>
<div class="h5 mb-0">${value.pivot.qty} DB</div>
</div>
</div>
</div>
<div class="pos-task-product-action">
<a href="#" class="btn btn-success">Complete</a>
<a href="#" class="btn btn-outline-default">Cancel</a>
</div>
</div>
</div>
</div>
`;
});
OrderView += `<div class="pos-task">
<div class="pos-task-info">
<div class="h3 mb-1" id=""><td>Üzenet: ${value.notes}</td></div>
<div><div><button type="button" class="btn btn-outline-theme rounded-0 w-150px data-status="${value.status}" data-order="${value.status}" id="order_update">Confirm Order</button></div></div>
<br>
<!-- You can safely remove this if not needed
<div class="mb-3">${value.product_id}</div>
<div class="h4 mb-8">${value.product_name}</div>
-->
<td>   </td>
<div class="mb-2">
<span class="badge bg-success text-black fs-14px">${value.status}</span>
</div>
<div><span class="text">${value.created_at}</span> Beérkezett</div>
</div>
<div class="pos-task-body">
<div class="fs-16px mb-3">
Completed: (1/4)
</div>
${productsList}
</div>
</div>`

});
$('#OrderView').html(OrderView);
}
})
}
OrderView();```

**Im currently trying to use this button inside the HTML ajax**<div><button type="button" class="btn btn-outline-theme rounded-0 w-150px data-status="${value.status}" data-order="${value.status}" id="order_update">Confirm Order</button></div>

我尝试使用processData: false，但它只是杀死进程和按钮不可用。请帮助。

Answer 1

您的问题是您有许多具有相同名称的标识符#。

id必须唯一。替换代码

$(document).on('click', 'button#order_update'

$(document).on('click', 'button.order_update'

---

和

<button type="button" class="btn btn-outline-theme rounded-0 w-150px data-status="${value.status}" data-order="${value.status}" id="order_update">Confirm Order</button>

<button type="button" class="btn btn-outline-theme rounded-0 w-150px order_update" data-status="${value.status}" data-order="${value.status}">Confirm Order</button>

你仍然有问题，你没有关闭类引用后w-150px，我关闭它在格式化代码