Parse URL with DOMXPath

Question

我不知道如何使用DOMXPath获取url。

<div class="row">
<div class='col-md-12'>
<div class="RAElencoCanali RAEC02 elem_1 row_odd RAEC1">
<p class="RACalDate">
<span class="data">
<span class="day">06</span>
<span class="mouth">mar</span>
</span></p> 
<h2><a title="Seminario: Confindustria Ancona" href="https://www.univpm.it/Confindustria_MarcheNord_seminario_on_line_-_marzo_2021">
<span>Seminario: Confindustria Ancona</span></a></h2>   
<p class="RADate">
18 marzo 2021</p>
<div class="RAFloatClear RARow1px">&nbsp;</div>   
</div>
</div>
</div>

对于php代码，我想获取链接，但我不能

$dom = new DOMDocument();
$dom->loadHTML($html);
$xpath = new DOMXPath($dom);
$titolo1 = $dom->getElementsByTagName('h2')->Item(3); 
$tagsTitolo = $xpath->query("*/a[@title='".$titolo1->nodeValue."']");

谢谢你的合作

Answer 1

使用说明:

$elements = $xpath->query('//h2/a/@href');
if($elements->length > 0) {
echo $elements->item(0)->nodeValue;
}