如何将if语句合并到另一个if语句中?

Question

我是Python的初学者;我正尝试着编写一款文本冒险游戏，鼓励用户探索一个拥有不同选择的房间。用户输入"1后，"我希望游戏通过另一个if语句输入更多选择。我该怎么做呢?如果这种方法不正确，我应该用什么函数来代替呢?我试过放入另一个if语句，但这会导致程序产生不同的结果，比如输出代码的不同部分而不是我想要的部分。下面是我现在的代码:

Name = input("What is your name, visitor?")
print(Name + (", you are being watched. Proceed carefully. A breeze of howling wind enters the room. Within the echo, something reaches out to you and offers a candle. Do you want to light the candle?"))
print("1 for YES")
print("2 for NO")
try:
Choice = int(input("What do you choose?"))
print("Choice:", Choice)
except ValueError:
print("Please input 1 or 2 only...")  
Choice = int(input("What do you choose?"))
if Choice == 1 :
print("A flickering candlelight bursts forth. You are blinded momentarily. When your eyes adjust, you see a table, drawer, and lamp in the room. You can check:")
print("1 for Table")
print("2 for Drawer")
print("3 for Lamp")
if Choice == 2 :
print("You sit in silence,  wondering what to do. Without sight, you're losing options. Eventually, you muster up the courage to stand up. You can't hear your own steps. Fear climbs up your throat. The floor gives way under your feet. You are swallowed by the darkness. GAME OVER.")
quit()
if not 1:
print("Please enter either 1 or 2.")
if not 2:
print("Please enter either 1 or 2")```

Answer 1

这段代码有几个问题，但是为了解决您的问题:将if嵌套在外部if中:

if Choice == 1 :
print("A flickering candlelight bursts forth. You are blinded momentarily. When your eyes adjust, you see a table, drawer, and lamp in the room. You can check:")
print("1 for Table")
print("2 for Drawer")
print("3 for Lamp")
Choice = int(input("What do you choose?"))
if Choice == 1:
# Do table stuff
elif Choice == 2:
# Do drawer stuff
elif Choice == 3:
# Do lamp stuff
else:
# Handle error