写入数组类不会计数

Question

代码运行，但我不能让cout工作。请帮助我，我是一个初学者，真的很难得到我的数组的内容输出。

cout << myArray[0].getSquareName();是从来不是cout的线。

#include <iostream>
#include <string>
#include <fstream>
using namespace std;
class cSquare {
public:
string SquareName;
string getSquareName() const;
void setSquareName(string);
friend std::istream & operator >> (std::istream & is, cSquare & s);
};
// set method
void cSquare::setSquareName(string squareName)
{
squareName = SquareName;
}
//square name get method
string cSquare::getSquareName() const
{
return SquareName;
}
ostream & operator << (ostream & os, const cSquare & s)
{
os << s.getSquareName() << ' ';
return os;
}
istream & operator >> (istream & is, cSquare & s)
{
is >> s.SquareName;
return is;
}
int main()
{
string discard;
int i = 0;
const int MAX_SIZE = 26;
ifstream monopoly("monopoly.txt", ios::in);
if (monopoly.is_open())
{
cSquare myArray[MAX_SIZE];
getline(monopoly, discard);
string sname; //string to store what I read in from my file
while (i < MAX_SIZE && monopoly >> sname)
{
myArray[i].setSquareName(sname);//stores the string read in into the array
cout << myArray[0].getSquareName(); //it never cout's this
i++;
}
}
}

Answer 1

您的setSquareName()方法将对象的SquareName成员分配给输入参数，这是错误的。你需要做相反的事情，例如:

void cSquare::setSquareName(string sname)
{
//sname = SquareName;
SquareName = sname;
}

同样，这一行:

cout << myArray[0].getSquareName();

应该是这样的:

cout << myArray[i];

有了这两个修改，代码就可以工作了。

演示