我已经为这个问题挣扎了几天了。我想最终将我的蛇游戏脚本转换为exe，供我的朋友玩。我想让蛇以同样的速度移动，不管窗户有多大。
例如：我现在的窗口大小是(400400(。如果我将大小增加到(800800(，蛇的移动速度会变慢。然而，蛇的速度在20个像素处是恒定的。随着窗口大小的增加，我的主游戏循环似乎以较慢的速度循环。
我知道蛇有更多的像素可以通过更大的窗口大小来遍历，但这对蛇的速度有什么影响？我认为解决方案在于我把蛇画到屏幕上的速度，但不能确定。
import pygame
import sys
import random
import math
import time
pygame.display.set_caption('Snake')
pygame.font.init()
game_running = True
width = 400
height = 400
size = (width, height)
window = pygame.display.set_mode(size) # our surface type
pygame.display.set_caption("Snake Game by Nick Rinaldi")
class Food:
def __init__(self, block_size, surface, x_loc, y_loc): # pass in color and random_x/random_y. block size is a constant
self.block_size = block_size
self.surface = surface # green
self.x_loc = x_loc
self.y_loc = y_loc
self.mask = pygame.mask.from_surface(self.surface)
def draw(self, window):
window.blit(self.surface, (self.x_loc, self.y_loc))
class Snake:
def __init__(self, block_size, surface, x_loc, y_loc):
self.block_size = block_size
self.surface = surface # red
self.x_loc = x_loc
self.y_loc = y_loc
self.body = []
self.direction = None
self.velocity = 20
self.mask = pygame.mask.from_surface(self.surface)
def draw(self, color, window, block_size):
self.seg = []
self.head = pygame.Rect(self.x_loc, self.y_loc, block_size, block_size)
pygame.draw.rect(window, color, self.head)
if len(self.body) > 0:
for unit in self.body:
segment = pygame.Rect(unit[0], unit[1], block_size, block_size)
pygame.draw.rect(window, color, segment)
self.seg.append(segment)
def add_unit(self):
if len(self.body) != 0:
index = len(self.body) - 1
x = self.body[index][0]
y = self.body[index][1]
self.body.append([x, y])
else:
self.body.append([1000, 1000])
def move(self, step):
for index in range(len(self.body) -1, 0, -1):
x = self.body[index-1][0]
y = self.body[index-1][1]
self.body[index] = [x, y]
if len(self.body) > 0:
self.body[0] = [self.x_loc, self.y_loc]
if self.direction == "right": # if specific constant, keep moving in direction
self.x_loc += self.velocity * step
if self.direction == "left":
self.x_loc -= self.velocity * step
if self.direction == "down":
self.y_loc += self.velocity * step
if self.direction == "up":
self.y_loc -= self.velocity * step
def collision(self, obj):
return collide(food)
def gameOver(snake):
white = pygame.Color(255, 255, 255)
display = True
while display:
window.fill(white)
score_font = pygame.font.SysFont("Courier New", 16)
score_label = score_font.render("Your score was: " + str(len(snake.body) + 1), 1, (0, 0, 0))
replay_label = score_font.render("To replay, click the mouse button", 1, (0, 0, 0))
window.blit(score_label, (50, 100))
window.blit(replay_label, (50, 130))
pygame.display.update()
for event in pygame.event.get(): # if we hit "x" to close out the game, close out the game.
if event.type == pygame.QUIT:
pygame.quit()
exit()
if event.type == pygame.MOUSEBUTTONDOWN:
main()
pygame.quit()
sys.exit()
clock = pygame.time.Clock()
def main():
game_over = False
x = 20 # x position
y = 20 # y position
block_snakes = []
pygame.init()
clock = pygame.time.Clock()
red = pygame.Color(255, 0, 0)
green = pygame.Color(0, 255, 0)
white = pygame.Color(255, 255, 255)
black = pygame.Color(0, 0, 0)
block_size = 20
randx_green = random.randrange(0, width, 20)
randy_green = random.randrange(0, height, 20)
randx_red = random.randrange(0, width, 20)
randy_red = random.randrange(0, height, 20)
red_square = pygame.Surface((block_size, block_size))
red_square.fill(red)
green_square = pygame.Surface((block_size, block_size))
green_square.fill(green)
snake = Snake(block_size, red_square, 20, 20) # create snake instance
food = Food(block_size, green_square, randx_green, randy_green) # create food instance
def redraw_window():
draw_grid(window, height, width, white)
while game_running:
dt = clock.tick(30) # time passed between each call
step = dt/1000
print(step)
FPS = 60
window.fill(black)
food.draw(window)
snake.draw(red, window, block_size)
redraw_window()
for event in pygame.event.get(): # if we hit "x" to close out the game, close out the game.
if event.type == pygame.QUIT:
pygame.quit()
exit()
keys = pygame.key.get_pressed()
if keys[pygame.K_RIGHT]: # sets direction attribute as a constant
snake.direction = "right"
if keys[pygame.K_LEFT]:
snake.direction = "left"
if keys[pygame.K_DOWN]:
snake.direction = "down"
if keys[pygame.K_UP]:
snake.direction = "up"
snake.move(step)
collision = collide_food(snake.x_loc, snake.y_loc, food.x_loc, food.y_loc)
if collision:
ac_rand_x = random.randrange(0, width, 20) # after collision, random x
ac_rand_y = random.randrange(0, height, 20) # after collision, random y
# check snake.direction.
food = Food(block_size, green_square, ac_rand_x, ac_rand_y)
food.draw(window)
snake.add_unit()
wall_collide = collide_wall(snake.x_loc, snake.y_loc)
if wall_collide:
gameOver(snake)
# break
for block in snake.body:
if snake.x_loc == block[0] and snake.y_loc == block[1]:
gameOver(snake)
pygame.display.update()
# clock.tick(FPS)
def collide_food(snake_x, snake_y, obj_x, obj_y):
distance = math.sqrt((math.pow(snake_x - obj_x, 2)) + (math.pow(snake_y - obj_y, 2)))
if distance < 20:
return True
else:
return False
def collide_wall(snake_x, snake_y):
if snake_x > width:
game_over = True
return game_over
if snake_y > height:
game_over = True
return game_over
if snake_x < 0:
game_over = True
return game_over
if snake_y < 0:
game_over = True
return game_over
def collide_self(snake_x, snake_y, body_x, body_y):
if (snake_x and snake_y) == (body_x and body_y):
return True
else:
return False
def draw_grid(window, height, width, color):
x = 0
y = 0
grid_blocks = 20
for i in range(height):
x += 20
pygame.draw.line(window, color, (x, 0), (x, height), 1)
for j in range(width):
y += 20
pygame.draw.line(window, color, (0, y), (height, y), 1)
# pygame.display.update()
def display_score():
score_font = pygame.font.SysFont()
def main_menu(width, height):
clock = pygame.time.Clock()
FPS = 60
width = width
height = height
run = True
title_font = pygame.font.SysFont("Courier New", 16)
title_font.set_bold(True)
white = pygame.Color(255, 255, 255)
while run:
window.fill(white)
title_label = title_font.render("Snake Game by Nick Rinaldi ", 1, (0, 0, 0))
sponser_label = title_font.render("Sponsored by @goodproblemsnyc", 1, (0, 0, 0))
window.blit(title_label, ((width/4, height/4)))
window.blit(sponser_label, ((width/4, height/4 + 30)))
pygame.display.update()
for event in pygame.event.get(): # if we hit "x" to close out the game, close out the game.
if event.type == pygame.QUIT:
pygame.quit()
exit()
if event.type == pygame.MOUSEBUTTONDOWN:
main()
pygame.quit()
main_menu(width, height)```
游戏中的瓶颈是函数draw_grid，它在窗口外画了太多的线。
def draw_grid(window, height, width, color): x = 0 y = 0 grid_blocks = 20 for i in range(height): x += 20 pygame.draw.line(window, color, (x, 0), (x, height), 1) for j in range(width): y += 20 pygame.draw.line(window, color, (0, y), (height, y), 1)
如果在窗口外绘制一条线，则该语句不会绘制任何内容，但嵌套的for循环仍在运行
此外，您不需要嵌套循环。您不希望为每条垂直线绘制19条水平线。您要绘制19条垂直线和19条水平线。因此1个CCD_ 2-循环就足够了。
使用range的步骤参数来定义垂直和水平线的位置列表
def draw_grid(window, height, width, color):
tile_size = 20
for p in range(tile_size, height, tile_size):
pygame.draw.line(window, color, (p, 0), (p, height), 1)
pygame.draw.line(window, color, (0, p), (height, p), 1)
如果大小是400*400像素，那么总像素160000以20像素的速率移动，因为像素较少，所以800*800板(320000像素(看起来速度更快，因为像素更少。找到一个方程来计算不同尺寸板上的正确速度。
真诚地，Zac