计算两个lat-long之间的距离，并使用php以米/km为单位显示

Question

我想计算两个纬度和经度之间的距离，如果输出距离小于km，则显示距离以米为单位，如谷歌地图"190米"；；截至目前，以英里为单位显示

<?php 
function distance($lat1, $lon1, $lat2, $lon2, $unit) {

$theta = $lon1 - $lon2;
$dist = sin(deg2rad($lat1)) * sin(deg2rad($lat2)) +  cos(deg2rad($lat1)) * cos(deg2rad($lat2)) * cos(deg2rad($theta));
$dist = acos($dist);
$dist = rad2deg($dist);
$miles = $dist * 60 * 1.1515;
$unit = strtoupper($unit);
if($miles <1km){
echo 'away from'.$miles .'meters';// distance in meters
}

else{
echo 'away from'$miles.'km';
} 
}

echo distance('17.360527','78.473542','17.361012','78.473062','m');
?>

Answer 1

我认为这对你有用：

<?php
function distance($lat1, $lon1, $lat2, $lon2, $unit) {

$theta = $lon1 - $lon2;
$dist = sin(deg2rad($lat1)) * sin(deg2rad($lat2)) +  cos(deg2rad($lat1)) * cos(deg2rad($lat2)) * cos(deg2rad($theta));
$dist = acos($dist);
$dist = rad2deg($dist);
$miles = $dist * 60 * 1.1515;
$unit = strtoupper($unit);
// Convert Miles To KM 
$dis_in_km = $miles * 1.609344;

if($dis_in_km < 1){
// Convert Miles to Miters
$dis_in_m = $miles * 1609.344;
echo 'away from '. round($dis_in_m,2).' meters';
}else{
echo 'away from '.round($dis_in_km,2).' km';
} 
}

echo distance('17.360527','78.473542','17.361012','78.473062','m');
?>