Firebase函数，响应不是有效的json对象

Question

我正在使用android studio开发一个基于角色的应用程序，因为我的项目需要创建用户和删除用户的管理权限，我在项目中使用了firebase admin-sdk。我试图删除多个帐户，但我遇到了问题。响应返回的json对象无效。在我的代码中，我试图处理可能的错误。但是，响应仍然返回一个无效的json对象。见下文

index.js

exports.deleteUser = functions.https.onCall(async (data,context) => {
try {
if(!context.auth) {
throw new AuthenticationError('Kimlik Doğrulaması Yapılmamış');
}
const uids = JSON.parse(data);
console.log(uids);
const callerUid = context.auth.uid;
const callerUser = await admin.auth().getUser(callerUid);
if(!callerUser.customClaims.admin && !callerUser.customClaims.superadmin) {
throw new NotAnAdminError('Bu işlemi sadece yöneticiler gerçekleştirebilir');
} 
const reference = admin.firestore().collection("Users");
const res = await admin.auth().deleteUsers(uids);
res.errors.forEach(element => console.log(element));
const successes = res.successCount;
const fails = res.failureCount;
console.log(fails);
console.log(successes);
if(fails===0) {
await uids.forEach(element => reference.doc(element).delete());
return {result:successes+' Öğrenci Silindi!'};
}else {
throw new functions.https.HttpsError('Silme Hatası','Bilinmeyen hata, 
silinemeyen öğrenci sayısı: '+fails);
}
}
catch(error) {
if(error.type === 'NotAnAdminError') {
throw new functions.https.HttpsError('Bu işlemi yapma yetkiniz 
yok.',error.message);
}else if(error.type === 'AuthenticationError') {
throw new functions.https.HttpsError('Kimlik Hatası',error.message);
}else {
throw new functions.https.HttpsError('internal ERROR from catch 
block',error.message);
}
}
});

安卓代码

private Task<String> deleteUsers(List<CheckableUser> users) {
List<String> idlist = new ArrayList<>();
for (CheckableUser user:users) {
idlist.add(user.getUid());
}
return mFunctions.getHttpsCallable("deleteUsers").call(jsonFormatted).
continueWith(new Continuation<HttpsCallableResult, String>() {
@Override
public String then(@NonNull Task<HttpsCallableResult> task) throws Exception {               
HashMap<String,Object> data = task.getResult().getData();
String result = data.get("result");
Log.d(TAG, "then: "+result);
return result;
}
});
mFunctions.getHttpsCallable("deleteUsers").call(jsonFormatted).continueWith(new 
Continuation<HttpsCallableResult, String>() {
@Override
public String then(@NonNull Task<HttpsCallableResult> task) throws Exception {
HashMap<String,Object> data = task.getResult().getData();
String result = data.get("result");
Log.d(TAG, "then: "+result);
return result;
}
});
}

deleteUsers(users).addOnCompleteListener(new OnCompleteListener<String>() {
@Override
public void onComplete(@NonNull Task<String> task) {
if (task.isSuccessful()) {
Snackbar snackbar = 
Snackbar.make(requireView().findViewById(R.id.constraintlayout),"Selected users are 
deleted",4000);
snackbar.show();
}else {
debugFirebase(task.getException());
}
}
});

private void debugFirebase(Exception e) {
if (e instanceof FirebaseFunctionsException) {
FirebaseFunctionsException ffe = (FirebaseFunctionsException) e;
Log.d(TAG, "debugFirebase: MESSAGE: "+ffe.getMessage());
Log.d(TAG, "debugFirebase: CODE: "+ffe.getCode());
Log.d(TAG, "debugFirebase: DETAILS: "+ffe.getDetails());
Log.e(TAG, "debugFirebase: EXCEPTION: ",ffe );
}
}

例外

com.google.firebase.functions.FirebaseFunctionsException: Response is not valid 
JSONobject.
Caused by: org.json.JSONException: Value <!DOCTYPE of type java.lang.String cannot be 
converted to JSONObject

Answer 1

您的函数被声明并导出为"deleteUser"；，但你在Android客户端中称之为"；deleteUsers"；，这是不相同的。字符串需要匹配。