使用带有后退按钮的UINavigation从SwiftUI推送UIViewController

Question

我需要从SwiftUI打开UIViewController，UINavigation有后退按钮。

目前，我已经通过ViewControllerRepresentable和NavigationLink实现了这一点，但我有两个Navigations SwiftUI(带后退按钮的NavigationLink(和没有后退按钮的默认UINavigation，我想执行这一操作，使我的默认UINavigation带有后退按钮并隐藏SwiftUI。

struct UIKitVc : UIViewControllerRepresentable {

let navigationController =  UINavigationController()
func updateUIViewController(_ uiViewController: UINavigationController, context: Context) {
}

func makeUIViewController(context: Context) -> UINavigationController {
let storyboard = UIStoryboard(name: "Main", bundle: nil)
let viewController = storyboard.instantiateViewController(withIdentifier: "SearchResult") as! SearchResultViewController
self.navigationController.addChild(viewController)
return self.navigationController
}
}

NavigationLink(destination: UIKitVc(){}

提前谢谢。

Answer 1

如果要使用NavigationView/NavigationLink，则不需要使用UINavigationController，只需在UIViewController上使用representable，如

struct UIKitVc : UIViewControllerRepresentable {

func updateUIViewController(_ uiViewController: UIViewController, context: Context) {
}
func makeUIViewController(context: Context) -> UIViewController {
let storyboard = UIStoryboard(name: "Main", bundle: nil)
let viewController = storyboard.instantiateViewController(withIdentifier: 
"SearchResult") as! SearchResultViewController
// ... make additional set up here if needed
return viewController
}
}