Django视图:根据模式名称(从URL获得)将用户重定向到模板

Question

我正试图根据用户的模式名称将其重定向到各种应用程序。到目前为止，我已经写了这篇文章：

def loginUser(request, url):

schema_list1 = ['pierre']
schema_lsit2 = ['itoiz']
if request.method == 'POST':
form = AuthenticationForm(data=request.POST)
t = urlparse(url).netloc
dbschema = '"' + t.split('.', 1)[0] + '"'
if form.is_valid():
user = form.get_user()
login(request, user)


if dbschema in schema_list1:
print('yes')
redirect = '/upload.html'
return HttpResponseRedirect(redirect)

elif dbschema in schema_list2:
print('yes')
redirect = '/dash2.html'
return HttpResponseRedirect(redirect)

else:
form = AuthenticationForm()
context = {
'form': form,
}
return render(request, 'loginUser.html', context)

我的问题是我得到了错误：

TypeError at /loginUser
loginUser() missing 1 required positional argument: 'url'
Request Method: GET
Request URL:    https://itoiz.exostock.net/loginUser
Django Version: 3.0.5
Exception Type: TypeError
Exception Value:    
loginUser() missing 1 required positional argument: 'url'
Exception Location: /home/ubuntu/exo/lib/python3.6/site-packages/django/core/handlers/base.py in _get_response, line 113

我是django的新手，我很困惑为什么会出现这个错误，尤其是因为我在其他地方使用了完全相同的方法，而且效果很好。我想知道是否有人能看到我缺少的东西。顺便问一下，还有其他方法可以获取用户的url吗？

Answer 1

你想做穷人的租户模式吗？

如果是，请使用https://github.com/bernardopires/django-tenant-schemas(我们已经用了好几年了，效果非常好。(还有一个，https://github.com/django-tenants/django-tenants它有点维护，但我从未使用过它——概念是一样的。

除此之外，改为这样做：

def login_user(request):  # we don't do camel-casing

# I don't know your exact use case, but having this in the view seems wrong..
schema_list1 = ['pierre']
schema_lsit2 = ['itoiz']
# This will be an empty "{}" if it's not a POST, meaning, you don't need the 
# extra if, it will work in both cases
form = AuthenticationForm(data=request.POST)
if request.method == 'POST':
dbschema, _, _ = request.get_host().partition('.')
if form.is_valid():
user = form.get_user()
login(request, user)

if dbschema in schema_list1:
print('yes')
redirect = '/upload.html'
return HttpResponseRedirect(redirect)
elif dbschema in schema_list2:
print('yes')
redirect = '/dash2.html'
return HttpResponseRedirect(redirect)
else:
raise Exception('HANDLE THIS!!!')
context = {
'form': form,
}
return render(request, 'loginUser.html', context)

Answer 2

当您提交表单时，您可能会在没有参数的情况下向"loginUser"发送请求。

另一件事是，您可能不需要将URL作为参数，只需从请求中获取即可：

request.build_absolute_uri((