Instagram网络抓取与硒Python问题

Question

我在从Instagram个人资料中抓取所有图片时遇到了问题，我正在滚动页面直到底部，然后找到所有图片"a"；标签最后总是我只得到最后30个图片链接。我认为驱动程序没有看到页面的全部内容。

#scroll
scrolldown = driver.execute_script("window.scrollTo(0, document.body.scrollHeight);var scrolldown=document.body.scrollHeight;return scrolldown;")
match=False
while(match==False):
last_count = scrolldown
time.sleep(2)
scrolldown = driver.execute_script("window.scrollTo(0, document.body.scrollHeight);var scrolldown=document.body.scrollHeight;return scrolldown;")
if last_count==scrolldown:
match=True
#posts
posts = []
time.sleep(2)
links = driver.find_elements_by_tag_name('a')
time.sleep(2)
for link in links:
post = link.get_attribute('href')
if '/p/' in post:
posts.append(post)

Answer 1

看起来像是先滚动到页面底部，然后才获取链接，而不是获取链接并在滚动循环中处理它们
因此，如果你想获得所有链接，你应该执行

links = driver.find_elements_by_tag_name('a')
time.sleep(2)
for link in links:
post = link.get_attribute('href')
if '/p/' in post:
posts.append(post)

在滚动内部，也在第一次滚动之前
类似这样的东西：

def get_links():
time.sleep(2)
links = driver.find_elements_by_tag_name('a')
time.sleep(2)
for link in links:
post = link.get_attribute('href')
if '/p/' in post:
posts.add(post)
posts = set()
get_links()
scrolldown = driver.execute_script("window.scrollTo(0, document.body.scrollHeight);var scrolldown=document.body.scrollHeight;return scrolldown;")
match=False
while(match==False):
get_links()
last_count = scrolldown
time.sleep(2)
scrolldown = driver.execute_script("window.scrollTo(0, document.body.scrollHeight);var scrolldown=document.body.scrollHeight;return scrolldown;")
if last_count==scrolldown:
match=True