如何在嵌入中显示当前URL

Question

<embed src="snippet.html">-我需要插入自定义url(othersite.com/directory/something/(+"搜索部分"；src属性内当前URL的。我得到了类似"；console.log(window.location.search("；可以帮助，但我如何将其连接/插入src？

简而言之，我的嵌入代码输出应该看起来像：<embed src="othersite.com/directory/something/astalavista">，当当前URL看起来像mysite.com/info/astalvista 时

我的HTML代码应该是什么样子？

我使用Wordpress。需要HTML代码。谢谢

Answer 1

试试这个

const loc = new URL(location.href);
const lastPath = loc.pathname.split('/').pop();
const embed = document.createElement('embed');
embed.src = `https://othersite.com/directory/something/${lastPath}`
document.body.appendChild(embed)

Answer 2

如果你想在HTML中正确地执行它，也许不是有史以来最好的JS，但你可以去：

some of your html...
<script>
let myUrl = "whatever"; // or echo some php variable here?
window.write(`<embed src="snippet.html/${myUrl}">`);
</script>
carry on with your html...