我如何设置一个变量的值是一个随机范围，变量设置有一个随机范围?

Question

我有一个变量叫做"number"范围是变量"one_answers";b"。这些范围变量本身就是范围。

from random import *
a = randint(1, 99)
b = randint(2, 100)
number = randint(a, b)
print(number)

当我尝试输入这段代码时，我偶尔会收到一个整数或得到这个错误:

Traceback (most recent call last):
File "main.py", line 6, in <module>
number = randint(a, b)
File "/nix/store/2vm88xw7513h9pyjyafw32cps51b0ia1-python3-3.8.12/lib/python3.8/random.py", line 248, in randint
return self.randrange(a, b+1)
File "/nix/store/2vm88xw7513h9pyjyafw32cps51b0ia1-python3-3.8.12/lib/python3.8/random.py", line 226, in randrange
raise ValueError("empty range for randrange() (%d, %d, %d)" % (istart, istop, width))
ValueError: empty range for randrange() (17, 6, -11)

Answer 1

需要确保传递给randint的第一个参数小于或等于第二个参数。如何:

from random import randint
a = randint(1, 99)
b = randint(a, 100)
number = randint(a, b)
print(number)

…这相当于:

from random import randint
number = randint(1, 100)
print(number)

Answer 2

randint(a, b)有条件

a <= b

由于您生成的a和b是随机范围，因此有时a大于b。您需要调整您的a和b范围，使a始终小于或等于b。

a = randint(1, 50)
b = randint(50, 100)

Answer 3

由于randint的范围需要由上下边界组成，因此当b随机低于a时，脚本偶尔会中断。为了防止这种情况，确保b不能低于a。一个例子:

from random import *
a = randint(1, 99)
b = randint(a, 100)
number = randint(a, b)
print(number)

Answer 4

使用它似乎可以完成您要求的工作。

import random
a = random.randint(1, 99)
b = random.randint(2, 100)
number = random.randint(a, b)
print(number)

我运行这个没有任何错误。