PHP加载多个XML数据而不编号

Question

我在尝试从XML文件加载多个数据时遇到了一些问题。我想加载所有XML数据，而不需要对它们进行编号[0]，[1]等，我该如何实现这一点?

PHP

<?php
echo"<center>";
$xml = simplexml_load_file('channels.xml') or die('Failed to read data');
echo $xml->channels[0]->name . "<br>";
echo "<img class='responsive' src='";
echo $xml->channels[0]->banner;
echo "'><br>";
echo "<form method='post' action='index.php'>";
echo "<input type='hidden' type='text' name='url' value='";
echo $xml->channels[0]->url;
echo "'><br>";
echo "<input type='submit' name='submit' value='PLAY CHANNEL'><br>";
$xml = simplexml_load_file('channels.xml') or die('Failed to read data');
echo $xml->channels[1]->name . "<br>";
echo "<img class='responsive' src='";
echo $xml->channels[1]->banner;
echo "'><br>";
echo "<form method='post' action='index.php'>";
echo "<input type='hidden' type='text' name='url' value='";
echo $xml->channels[1]->url;
echo "'><br>";
echo "<input type='submit' name='submit' value='PLAY CHANNEL'><br>";
echo"</center>";
if(isset($_POST['url'])) {
shell_exec("sudo killall player.bin");
shell_exec("sudo player `youtube-dl -g ".($_POST['url'])." `>> /dev/null &");
}
?>

XML

<?xml version="1.0" encoding="utf-8"?>
<data>
<channels>
<banner>https://upload.wikimedia.org/wikipedia/commons/thumb/d/de/Sky-news-logo.svg/768px-Sky-news-logo.svg.png</banner>
<url>https://www.youtube.com/channel/UCoMdktPbSTixAyNGwb-UYkQ/live</url>
</channels>
<channels>
<banner>https://lh3.googleusercontent.com/proxy/DqTJr6u-LpXfWyrJscDsoa_XdZsXLTm1PXDLw_eJYRAlwx0RtNO4thah_YQhKk-vWmeSHkIfSGsClFIQmTWDS0iNGM3VeeEXrSzYSVPRFyEf5NQ9TVw0B9KYXg</banner>
<url>https://www.youtube.com/channel/UCeY0bbntWzzVIaj2z3QigXg/live</url>
</channels>
</data>

Answer 1

如PHP手册中的示例所示，您可以使用普通的foreach循环遍历具有相同名称的元素:

$xml = simplexml_load_file('channels.xml') or die('Failed to read data');
foreach ( $xml->channels as $channelsElement ) {
echo $channelsElement->name;
}