Python 3.10版本在尝试向图像添加水印时产生错误

Question

注意:所有3.9版本的代码都可以完美地创建水印图像。

我创建了这个项目，以适应水印交叉，完美地适合图像的大小，但在这行代码:

paste_mask = watermark.split()[3].point(lambda i: i * TRANSPARENCY / 100.)

它产生这个错误:

File "c:UsersComputadorDesktopPythonWatermark.py", line 29, in watermark_with_transparency
paste_mask = watermark.split()[3].point(lambda i: i * TRANSPARENCY / 100.)
File "C:UsersComputadorAppDataLocalProgramsPythonPython310libsite-packagesPILImage.py", line 1723, in point
return self._new(self.im.point(lut, mode))
TypeError: 'float' object cannot be interpreted as an integer

完整代码为:

from PIL import Image
def watermark_with_transparency(input_image_path,
output_image_path,
watermark_image_path):
TRANSPARENCY = 10
angle = 30
base_image = Image.open(input_image_path)
w_img, h_img = base_image.size
basewidth = w_img
watermark = Image.open(watermark_image_path)
watermark = watermark.rotate(angle, expand=True)
wpercent = (basewidth / float(watermark.size[0]))
hpercent = h_img / float(watermark.size[1])
if wpercent < hpercent:
hsize = int((float(watermark.size[1]) * float(wpercent)))
watermark = watermark.resize((basewidth, hsize), Image.ANTIALIAS)
else:
wsize = int((float(watermark.size[0]) * float(hpercent)))
watermark = watermark.resize((wsize, h_img), Image.ANTIALIAS)
w_logo, h_logo = watermark.size
center_y = int(h_img / 2)
center_x = int(w_img / 2)
top_y = center_y - int(h_logo / 2)
left_x = center_x - int(w_logo / 2)
if watermark.mode != 'RGBA':
alpha = Image.new('L', (w_img, h_img), 255)
watermark.putalpha(alpha)
paste_mask = watermark.split()[3].point(lambda i: i * TRANSPARENCY / 100.)
base_image.paste(watermark, (left_x, top_y), mask=paste_mask)
base_image.save(output_image_path)

图像中的模型是好的，我视图中的值是正确的，我应该修改什么才能在这个新的python版本中工作?

Answer 1

尝试:

paste_mask = watermark.split()[3].point(lambda i: int(i * TRANSPARENCY / 100.))

似乎在移动到Python 3.9时，type inference发生了变化，并且值没有自动转换到int。