While循环在查询中被跳过;没有错误报告

Question

这段代码有问题，尽管没有报告错误。程序只是跳过两个while循环。有人能帮帮我吗?

def play_game():
#print(logo)
user_cards = []
computer_cards = []
is_game_over = False
for _ in range(2):
user_cards.append(deal_card()) #deal_card() is predifined function
computer_cards.append(deal_card())
user_score = calculate_score(user_cards)
computer_score = calculate_score(computer_cards) #calculate score is predefined function
print(f"   Your cards: {user_cards}, current score: {user_score}")
print(f"   Computer's first card: {computer_cards[0]}")
if user_score == 0 or computer_score == 0 or user_score > 21:
is_game_over = True
else:
while is_game_over:
user_should_deal = input("Type 'y' to get another card, type 'n' to pass: ")
if user_should_deal == "y":
user_cards.append(deal_card())
else:
is_game_over = True
while computer_score != 0 and computer_score < 17:
computer_cards.append(deal_card())
computer_score = calculate_score(computer_cards)
print(f"   Your final hand: {user_cards}, final score: {user_score}")
print(f"   Computer's final hand: {computer_cards}, final score: {computer_score}")
print(compare(user_score, computer_score))
while input("Do you want to play a game of Blackjack? Type 'y' or 'n': ") == "y":
clear()
play_game()

Answer 1

你应该在while条件之前添加一个not关键字，因为它现在声明它将在游戏结束时继续运行，并且你的变量开始为false，因此它现在甚至不会进入一次。

修复while循环:

while not is_game_over:
user_should_deal = input("Type 'y' to get another card, type 'n' to pass: ")
if user_should_deal == "y":
user_cards.append(deal_card())
else:
is_game_over = True
while computer_score != 0 and computer_score < 17:
computer_cards.append(deal_card())
computer_score = calculate_score(computer_cards)