处理列表时出现问题
试图找出如何编号元素，如果它们出现不止一次，从第二次出现，我想在'@'附近添加数字:
例如:
['example@company.com', 'example@company.com', 'none@comapny.com','example@company.com']
需要输出:
['example@company.com', 'example2@company.com', 'none@comapny.com','example3@company.com']
目前代码:
count_apper=Counter(mails_list)
for values in count_apper.items():
for mail in mails_list:
if values[0]==mail:
number+=1
temp_var=mail.split("@")
temp_var[0]=temp_var[0]+f"{number}"
temp_var="@".join(temp_var)
print(temp_var)
number=1
输出:
example1@company.com
example2@company.com
example2@company.com
none2@company.com
我想我的答案是基于一个collections.Counter()。它会帮你做一些工作。
import collections
addresses = ['example@company.com', 'example@company.com', 'none@comapny.com', 'example@company.com']
results = []
for address, count in collections.Counter(addresses).items():
# add a "first" address as is
results.append(address)
# If there were other occurrences add them
for i in range(1, count):
results.append(f"{i+1}@".join(address.split("@")))
print(results)
这应该给你:
['example@company.com', 'example2@company.com', 'example3@company.com', 'none@comapny.com']
您可以迭代列表并使用dict来跟踪特定地址的出现次数。要在@符号前添加文字，可以使用str的.split方法。一个可能的实现如下:
addresses = ['example@company.com', 'example@company.com', 'none@comapny.com', 'example@company.com']
occurence_count = {}
transformed = []
for a in addresses:
count = occurence_count.get(a, 0) + 1
occurence_count[a] = count
name, domain = a.split('@')
if count > 1:
transformed.append(f'{name}{count}@{domain}')
else:
transformed.append(a)
print(transformed)
试试这个
j=['example@company.com', 'example@company.com', 'none@comapny.com','example@company.com']
count=1
k=j.copy()
for i in range(len(j)):
if k.count(k[i])>1:
m=[char for char in j[i]]
m.insert(j[i].index('@'),str(count)
)
count+=1
j[i]=''.join(m)
print (j)