我的代码片段
movie_female_cast = pd.read_sql_query(""" SELECT TRIM(MC.MID), COUNT(P.Gender),P.Gender FROM M_Cast MC
INNER JOIN Person P
ON P.PID = TRIM(MC.PID)
WHERE P.Gender IN ('Male',NULL, 'Female')
GROUP BY MC.MID
""",conn)
\
——输出"
TRIM(MC.MID) COUNT(P.Gender) Gender
0 tt0021594 8 Male
1 tt0026274 20 Male
2 tt0027256 13 Male
3 tt0028217 10 Male
4 tt0031580 44 Female
... ... ... ...
3468 tt8581230 8 Female
3469 tt8698956 10 Male
3470 tt8852558 17 Male
3471 tt8932884 3 Male
3472 tt9007142 9 Male
'''
在这里的p .性别栏,有3个类别-女性,男性,Null。现在我想找到电影id,上面提到的所有3个类别的计数,现在上面的代码计数实际上并没有考虑NULL值,只返回男性和女性类别。有谁能帮帮我吗
对于count,不指定p. gender:
movie_female_cast = pd.read_sql_query(""" SELECT TRIM(MC.MID), COUNT(*),P.Gender FROM M_Cast MC
INNER JOIN Person P
ON P.PID = TRIM(MC.PID)
WHERE P.Gender is NULL or p.Gender IN ('Male','Female')
GROUP BY MC.MID, p.gender
""",conn)