Python从列表返回不区分大小写的字符串，如果它包含不区分大小写的子字符串

Question

如何返回不区分大小写的字符串fromlist，如果包含不区分大小写的子字符串？ 返回的字符串应该是不区分大小写

我能够从列表返回string，但是我使用小写方法。我想在不修改

的情况下将其返回到原始状态

entriesList = ['CSS', 'Django', 'Git', 'HTML', 'Python']
substring = "g"
def substringSearch(substring, entriesList):
return [string for string in (string.casefold() for string in entriesList) if substring in string] 

print(substringSearch(substring, entriesList))

结果:

['django', 'git']

我想要什么:

['Django', 'Git']

Answer 1

你可以在理解题中只使用lower()或casefold()。

[string for string in entriesList if substring in string.casefold()]

您不需要为此创建一个新的生成器。这将给你:

entriesList = ['CSS', 'Django', 'Git', 'HTML', 'Python']
substring = "g"
def substringSearch(substring, entriesList):
return [string for string in entriesList if substring in string.casefold()] 

print(substringSearch(substring, entriesList))
# ['Django', 'Git']