创建一个程序，将输入的多个句子修改为第一个字母大写的python

Question

此代码的问题如下：

1. 我输入的内容在第一句话之后被截断。

2. 当询问用户是否希望再次运行程序时，代码无法再次运行。

3. 当输入其他输入时，程序不会结束。在下面的代码之后，我粘贴了运行程序时的外观。

def main ():
string=input('Enter sentences to be modified:') #enter sentences
sentence=string.split('.')
for i in sentence:
print ("Your modified setences is:" + i.strip().capitalize()+". ",end='')
print ()
rerun ()

def rerun ():
while True:
again = input("Run again? ") #asks user if they want to run again
if 'y' in again:
main ()  #reruns def main
else:
print("bye") #ends program 

main()

代码返回：

Enter sentences to be modified:yes. hello
Your modified setences is:Yes. 
Run again? y
Run again? n
Run again? 

Answer 1

你需要break退出while循环，如果他们说不，你就没有中断，所以它永远不会结束。你的if声明不在while之下。。。

def run():
string=input('Enter sentences to be modified:') #enter sentences
sentence=string.split('.')
for i in sentence:
print ("Your modified setences is:" + i.strip().capitalize()+". ",end='')

def main():
while 1:
run()
again = input("Run again? Y/N ") #asks user if they want to run again
if again.lower() != 'y': #clean break on N
break

main()

Answer 2

您已经将main()函数定义为递归函数，而不必递归

def main ():
while True:
string = input('Enter sentences to be modified: ')
sentence = string.split('.')
for i in sentence:
print("Your modified setences is: " + i.strip().capitalize() + ". ")
print()
while True:
again = input("Run again? ")
if 'y' in again:
break # breaks out of inner while loop, not outer
else:
return print("bye") # prints "bye" and ends function

main()

Answer 3

while True:将永远运行，因为if 'y' in again和else语句在循环之外。您还需要缩进该表达式！在Python中，缩进是极其重要的。