为什么elif语句优先于我的if语句

Question

所以我有一个猜数字的游戏，我以前的所有代码都运行良好，你可能会看到我在屏幕上打印了随机生成的数字。但是，当我猜对了数字时，我仍然会被告知我错了？

num = randrange(0, 100)
if num > 0 and num < 50:
print("The number is greater than 0 but smaller than 50")
elif num > 50 and num < 100:
print("The number is smaller than 100 but greater than 50")
print(num)
print('Start Guessing')
a = input()

a = input()
if a == num:
print ("You got the correct number, woohoo")
elif num > 0 and num < 20:
print ("Hint: The number is bigger than 0 but smaller than 20")
elif num > 20 and num < 40:
print ('Hint: The number is bigger than 20 but smaller than 40')
elif num > 40 and num < 60:
print ('Hint: The number is bigger than 40 but smaller than 60')
elif num > 60 and num < 80:
print ('Hint: The number is bigger than 60 but smaller than 80')
elif num > 80 and num < 100:
print ('Hint: The number is bigger than 80 but smaller than 100')

很抱歉代码看起来很奇怪，我以前从未使用过这个网站。

Answer 1

您的代码看起来是Python。您应该在标记中指出这一点。此外，由于Python-if语句依赖于缩进，因此您应该使用适当的缩进来发布代码。

代码中：

a = input()
if a == num:

您正在将字符串与数字进行比较。您应该将a强制转换为int。

if int(a) == num: