我想计算不同的值,并报告它们在SQL中的出现情况。问题是,我需要计算不同列上的出现次数,然后为每列报告每个值的出现次数。所以,假设我从一个名为Result:的表中得到了这样的数据
所有者Id | 飞行员Id | 教练Id>||
---|---|---|---|
A | 1 | 2 | 3 |
B | 2 | 2 | 3 |
C | 3 | <1>3 |
我认为您需要将列取消平移为行,然后计算每个值的出现次数。你可以做:
select v.id,
sum(case when v.col = 'owner' then 1 else 0 end) owner,
sum(case when v.col = 'pilot' then 1 else 0 end) pilot,
sum(case when v.col = 'coach' then 1 else 0 end) coach
from mytable t
cross apply (values (t.ownerid, 'owner'), (t.pilotid, 'pilot'), (t.coachid, 'coach')) as v(id, col)
group by v.id
DB Fiddle上的演示:
id |所有者|飞行员|教练-:|----:|----:|----:1|1|1|02|1|2|03|1|0|3
使用基本的SQL
命令也是如此。保证在每个DBMS上工作:
SELECT
ids.id,
SUM(CASE WHEN ro.ownerid = ids.id THEN 1 ELSE 0 END) AS Owner,
SUM(CASE WHEN po.pilotid = ids.id THEN 1 ELSE 0 END) AS Pilot,
SUM(CASE WHEN co.coachid = ids.id THEN 1 ELSE 0 END) AS Coach
FROM (
SELECT ownerID AS id FROM result UNION
SELECT pilotID FROM result UNION
SELECT coachID FROM result
) ids
LEFT JOIN result ro ON ids.id = ro.ownerid
LEFT JOIN result po ON ids.id = po.pilotid
LEFT JOIN result co ON ids.id = co.coachid
GROUP BY ids.id
在SQLFiddler 中