Send回复邮件线程

Question

我正在尝试根据以下标准回复电子邮件:

扫描收件箱看不见的邮件与特定的主题内容，如果有邮件满足这些条件，然后:发送回回复消息给发件人说"某事"，如果这些条件不满足，然后发送回回复消息给发件人说"某事"。

这是我目前想到的:

import imaplib
import email
import smtplib

username = '[e-mail]'
password = 'xxxx'

imap_server = imaplib.IMAP4_SSL('smtp.gmail.com')
imap_server.login(username, password)
imap_server.select('INBOX')
result, data = imap_server.search(None, '(UNSEEN)')
email_ids = data[0].split()
for email_id in email_ids:
result, data = imap_server.fetch(email_id, "(RFC822)")
raw_email = data[0][1]
email_message = email.message_from_bytes(raw_email)
subject = email_message["Subject"]
if subject == "SOME SPECIFIC CONTENT":
reply = email.message.EmailMessage()
reply["To"] = email_message["From"]
reply["Subject"] = "Re: " + email_message["Subject"]
reply["In_Reply-To"] = email_message["From"]

server = smtplib.SMTP('smtp.gmail.com', 587)
server.ehlo()
server.starttls()
server.login(username, password)
server.sendmail(username, reply["In_Reply-To"], 'Subject: Criteria metnnThank you.')
server.quit()
else:

reply = email.message.EmailMessage()
reply['To'] = email_message['From']
reply['Subject'] = "RE:" + email_message['Subject']
reply["In_Reply-To"] = email_message["From"]

server = smtplib.SMTP('smtp.gmail.com', 587)
server.ehlo()
server.starttls()
server.login(username, password)
server.sendmail(username, reply["In_Reply-To"], 'Subject: Criteria not metnThank you.')
print('Sending email')
server.quit()
imap_server.close()

它发送电子邮件，但没有所需的线程，只是发送一个新的电子邮件，而不是实际回复发件人。

任何关于如何修改代码的建议，所以它实际上发送一个回复与所需的线程?

提前谢谢你。

Answer 1

就像评论提到的那样，您应该使用原始消息的message - id，而不是发送者地址。

同时，您应该服从Reply-To:并添加References:。

reply = email.message.EmailMessage()
reply["To"] = email_message["Reply-To"] or email_message["From"]
reply["Subject"] = "Re: " + email_message["Subject"]
reply["In_Reply-To"] = email_message["Message-Id"]
reply["References"] = (email_message["References"] or "") + " " + email_message["Message-Id"]

正确地说，References:标题应该从中间修剪，如果它太长。

一些供应商有他们自己的非标准线程扩展;特别是，Microsoft的Thread-Id:等标头可能最好忽略。