PHP 意外'public'

Question

我的PHP应用程序出现了这个错误

(syntax error, unexpected 'public' (T_PUBLIC), expecting variable (T_VARIABLE) ln6)

我还没有找到解决方案

class User
{
public const STATUS_ACTIVE = 'active';
public const STATUS_INACTIVE = 'inactive';
public function __construct(public string $username, public string $status = self::STATUS_ACTIVE)
{
}
}

Answer 1

参数中不应该有public、private或protected这样的访问修饰符。因为任何函数的形参都是输入，所以设置public、private或protected没有任何意义。

<?php
class User
{
public const STATUS_ACTIVE = 'active';
public const STATUS_INACTIVE = 'inactive';

public function __construct( string $username,  string $status = self::STATUS_ACTIVE)
{
}
}