主函数不工作，由于一个方法有参数?方法Height(int, int)不适用于arguments()

Question

// Patrik Maco
// 18/10/21
// VERSION 1 
// Write a program that allows the user to input the length, width and height of a room (cm) - volme of balloon (m^3) prints the volume of the room in m^3 and the amount of balloons needed to fill the room.
import java.util.Scanner; 
class volume 
{      
public static void main (String [] a)
{     
Run();
System.exit(0);
}
public static int Length()
{              
Scanner scanner  = new Scanner(System.in);
System.out.println("Enter Values as whole numbers- not as decimals. Do not include measurement. Good example : 5,7,9 Bad example: 3.2, 5cm");
System.out.println("Length of room (in cm) ? ");
length = scanner.nextInt(); 
return length;
} 
public static int Width()
{
Scanner scanner = new Scanner(System.in);
System.out.println("Enter Values as whole numbers- not as decimals. Do not include measurement. Good example : 5,7,9 Bad example: 3.2, 5cm");
System.out.println("Width of room (in cm) ? ");
int width = scanner.nextInt();
return width;
} 
public static int Height(length, width)
{ 
Scanner scanner = new Scanner(System.in);
System.out.println("Enter Values as whole numbers- not as decimals. Do not include measurement. Good example : 5,7,9 Bad example: 3.2, 5cm");
System.out.println("Height of room (in cm) ? ");
int height = scanner.nextInt();
return height;
System.out.println("Enter the volume of the baloon in M cubed");
float volume_b;
volume_b = scanner.nextFloat();
float RoomVolume;
RoomVolume = ( height * length * width);
System.out.println("The volume of the room is : " + RoomVolume);
float balloon3;
balloon3 = RoomVolume/1000000;
float BalloonAmount;
BalloonAmount = balloon3/volume_b;
int n;
n = (int)BalloonAmount;
System.out.println("The number of balloons needed is : " + n);
}

public static void Run()
{
int length = Length();
int width =  Width();
int height = Height();
}
}

方法Run()返回一个错误

方法Height(int, int)不适用于arguments()。

我是很新的编码，我想一个解释，如果可能的话，我怎么能解决这个问题?

Height在它自己的方法中包含两个参数，但是如果我在Run()中输入相同的参数，我的程序不会运行

Answer 1

您的方法Height存在多个问题。

1. 在Java中，所有参数都需要指定它们的类型，所以应该声明为

public static int Height(int length, int width)

2. 无条件返回语句后的所有代码都不可达

return height;
// any code after this point is unreachable

3. 如果一个方法有参数，你需要显式地提供它们:

public static void Run()
{
int length = Length();
int width =  Width();
int height = Height(length, width); // you need to pass length and width!
}

其他观察结果:

• 不需要在main的末尾显式地调用System.exit(0)，程序将在此时自动结束。
• 在Java中，将字段和类视为名词，将方法视为动词并相应地命名是一种非常普遍的命名约定。此外，类名通常以大写字母SomeClassName开头，而方法名通常以小写字母doSomething()开头。