Paypal curl_setopt($ch，带有PHP变量的CURLOPT_POSTFIELDS

Question

早间

尝试使用PHP和PayPal API将自定义PayPal订阅添加到我的网站。我以前没有真正使用过PHP或Curl，所以这需要一段时间，但我已经设法编写了一个脚本，从沙箱中获得访问令牌，并链接到您可以订阅的现有订阅计划。下面的代码很有效。。。

curl_setopt($ch, CURLOPT_POSTFIELDS, "n  {n   "plan_id":$planID,n   "start_time":$startTime,n      "application_context": {n        "brand_name": "Sleep Happy Mattress",n        "locale": "en-US",n        "shipping_preference": "SET_PROVIDED_ADDRESS",n        "user_action": "SUBSCRIBE_NOW",n        "payment_method": {n          "payer_selected": "PAYPAL",n          "payee_preferred": "IMMEDIATE_PAYMENT_REQUIRED"n        },n        "return_url": "https://example.com/returnUrl",n        "cancel_url": "https://example.com/cancelUrl"n      }n    }");

然而，每当我试图将planID和start_time作为php变量包含在curl_setopt($ch，CURLOPT_POSTFIELDS)中时，我都会收到一个"请求格式不正确、语法不正确或违反模式"的错误。

$planID = 'P-25Y56437062492726MFWZ4GI';
$startTime = '2021-10-22T00:00:00Z';

//由curl生成到PHP：http://incarnate.github.io/curl-to-php/

$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, 'https://api-m.sandbox.paypal.com/v1/billing/subscriptions');
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_POST, true);
//curl_setopt($ch, CURLOPT_POSTFIELDS, "n  {n   "plan_id": "P-25Y56437062492726MFWZ4GI",n   "start_time": "2021-10-22T00:00:00Z",n      "application_context": {n        "brand_name": "Sleep Happy Mattress",n        "locale": "en-UK",n        "shipping_preference": "SET_PROVIDED_ADDRESS",n        "user_action": "SUBSCRIBE_NOW",n        "payment_method": {n          "payer_selected": "PAYPAL",n          "payee_preferred": "IMMEDIATE_PAYMENT_REQUIRED"n        },n        "return_url": "https://example.com/returnUrl",n        "cancel_url": "https://example.com/cancelUrl"n      }n    }");
curl_setopt($ch, CURLOPT_POSTFIELDS, "n  {n   "plan_id":$planID,n   "start_time":$startTime,n      "application_context": {n        "brand_name": "Sleep Happy Mattress",n        "locale": "en-US",n        "shipping_preference": "SET_PROVIDED_ADDRESS",n        "user_action": "SUBSCRIBE_NOW",n        "payment_method": {n          "payer_selected": "PAYPAL",n          "payee_preferred": "IMMEDIATE_PAYMENT_REQUIRED"n        },n        "return_url": "https://example.com/returnUrl",n        "cancel_url": "https://example.com/cancelUrl"n      }n    }");

我的串联是错误的，还是变量需要先以某种方式进行操作，或者两者兼有？？

非常感谢的帮助

Chris

Answer 1

创建如下JSON字符串：

$data = [
'plan_id' => $planID,
'start_time' => $startTime,
'application_context' => [
'brand_name' => 'Sleep Happy Mattress',
'locale' => 'en-US',
'shipping_preference' => 'SET_PROVIDED_ADDRESS',
'user_action' => 'SUBSCRIBE_NOW',
'payment_method' => [
'payer_selected' => 'PAYPAL',
'payee_preferred' => 'IMMEDIATE_PAYMENT_REQUIRED'
],
'return_url' => 'https://example.com/returnUrl',
'cancel_url' => 'https://example.com/cancelUrl'
],    
];

然后你可以检查嵌套etc是否正确(请注意，我不知道上面的内容是否正确，我只是从你的问题中复制了它)，如果你json_encode它，你将创建格式良好的JSON。

$jsonEncoded = json_encode($data);

Answer 2

不要指定或包含start_time，除非您希望在结账时不显示金额。

您的问题是没有在变量值周围加引号，这对于JSON字符串语法来说是必要的。观察：

"plan_id": "$planID",

---

使用json_encode()从数组对象构造字符串会更好。