我有两个表:
人:
id,first_name,colorid
1,Mona,1
2,Davita,1
3,Mona,3
4,Davita,3
5,Marya,3
6,Mona,2
7,Whitby,3
8,Hardy,1
9,Hardy,2
10,Haskel,3
和颜色表:
id,color
1,Green
2,Black
3,Red
我想找到具有颜色表中所有颜色的first_names。
my attempt is:
SELECT DISTINCT P.first_name AS NAMES
FROM Persons P
JOIN Colors C ON C.id= P.colorid;
正确吗?
select first_name
from person
group by first_name
having count(distinct colorid) = (select count(*) from color)