根据嵌套值将对象阵列编组为二维阵列

Question

我有一个类似的对象数组

array1 = [{data: ..., name: a}, {data: ..., name: b}, {data: ..., name: a}, {data: ..., name: c}, {data: ..., name: c}, {data: ..., name: b}]

我想以这样一种方式对其进行排序，即在子阵列中按名称对其进行分组

array2 = [
[{data: ..., name: a}, {data: ..., name: a}, {data: ..., name: a}],
[{data: ..., name: b}, {data: ..., name: b}],
[{data: ..., name: c}]
]

我并不总是知道名字会是什么，所以我不能手动做'ifname==='a'等。

Answer 1

实际上这是grouping没有排序。

这可以通过循环技术来完成。我在这里使用Array.reduce

const array1 = [{ data: 'some value', name: 'a' }, { data: 'some value', name: 'b' }, { data: 'some value', name: 'a' }, { data: 'some value', name: 'c' }, { data: 'some value', name: 'c' }, { data: 'some value', name: 'b' }];
const array2 = array1.reduce((acc, curr) => {
const node = acc.find(item => item.find(subItem => subItem.name === curr.name));
if(node) {
node.push(curr)
} else {
acc.push([curr])
}
return acc;
}, []);
console.log(array2);

Answer 2

您可以在此处使用Array.reduce()按name对数据进行分组。我们为每个存在的名称创建一个具有属性的对象，并将任何匹配的值附加到该值的数组中。然后我们使用Object.values()来创建我们想要的数组。

array1 = [{data: {}, name: 'a' }, {data: {}, name: 'b'}, {data: {}, name: 'a'}, {data: {}, name: 'c'}, {data: {}, name: 'c'}, {data: {}, name: 'b'}];
const grouped = Object.values(array1.reduce((acc, cur) => { 
acc[cur.name] = [...(acc[cur.name] || []), cur];
return acc;
}, {}));
console.log('Grouped:', grouped);

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Answer 3

请尝试以下代码

let objMap = {};
array1.map(arr=>{
if(!objMap[arr.name]){
objMap[arr.name]=[]
}
objMap[arr.name].push(arr)
})
console.log(Object.values(objMap));

Answer 4

只需添加一些对象映射即可解决。

array1 = [{data: {}, name: 'a'},{data: {}, name: 'a'}, {data: {}, name: 'b'}, {data: {}, name: 'a'}, {data: {}, name: 'c'}, {data: {}, name: 'c'}, {data: {}, name: 'c'}, {data: {}, name: 'b'},{data: {}, name: 'c'}];
newObject = {};
array1.forEach((object)=>{
if((!newObject[object.name])){
newObject[object.name] = [object];  
} else {
newObject[object.name].push(object);
}
});
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array2 = Object.values(newObject);
console.log(array2);