当满足条件时停止for循环或while循环

Question

我是编程新手。目标是按顺序计数list中的数字，但是当满足或接近条件时，循环必须停止，但不能超过条件。

例如:list = [4,4,4,3,3]，条件= 11预期输出将是4+4=8，因为另一个4将超出条件(4+4+4=12)。

list = [4,4,4,3,3]
condition = 11
def for_fun(list, condition):
sum_of_sizes = 0
for i in list:
sum_of_sizes += i
if sum_of_sizes <= condition:
break
return sum_of_sizes

我发现for循环更容易工作，尽管while循环可能更适合这项任务。

Answer 1

将while添加到@matle的解中:

list = [4,4,4,3,3]
condition = 11
def for_fun(list, condition):
sum_of_sizes = 0
index = 0
while True:
if sum_of_sizes + list[index] > condition:
break
sum_of_sizes += list[index]
index += 1
return sum_of_sizes

print(for_fun(list, condition))

请尽量避免覆盖python关键字，如list!

Answer 2

我建议您检查您的下一个sum_of_sizes是否大于或等于您的条件，如果是这种情况，则中断。如果没有，就继续从列表中添加项目。此外，list是一个内置函数，所以请将list命名为其他函数，如input_list:

input_list = [4,4,4,3,3]
condition = 11
def for_fun(input_list, condition):
"""A function that adds up numbers and breaks if the next iteration would exceed condition"""

# initial sum of numbers
sum_of_sizes = 0

# iterate over your input list
for i in input_list:
# if the next sum of numbers would exceed condition, break
if sum_of_sizes+i > condition:
break
# add up numbers
sum_of_sizes += i
# return the sum at the end
return sum_of_sizes
# call and print your function, hand over your variables input_list and condition
print(for_fun(input_list=input_list, condition=condition))