操作模型的属性

Question

是否有一种方法可以将模型的属性操作为另一个属性?

我需要生成FullName基于所提供的LastName和FirstName

public class User
{
public string Username { get; set; } = null!;
public string Role { get; set; } = null!;
public int EmployeeID { get; set; }
public string FullName { get; set; } = null!; //CONCAT FROM LastName & FirstName
public string LastName { get; set; } = null!;
public string FirstName { get; set; } = null!;
public Division Division { get; set; } = null!;
}

Answer 1

用public string FullName => LastName +" "+ FirstName;
代替public string FullName {get;set;}

同样，真的没有必要指定= null作为引用类型属性的默认值——引用类型的默认值已经是null了。

Answer 2

尝试:

public string FullName
{
get { return string.Format("{0} {1}", FirstName, LastName); }
}

Answer 3

您可以通过使FullName属性仅为getter来连接FirstName和LastName:

public string LastName { get; set; };
public string FirstName { get; set; };   
public string FullName 
{
get { return LastName + " " + FirstName; }
}