我一直在学习Bash,我的老师做了一个让我困惑的练习。
我正在努力在单词前面添加空格。
代码应该考虑到每个单词的字符数量,并调整星号和空格的数量,使其始终对齐。
应该是这样的:
***********
* Hello *
* World *
* good *
* etceter *
***********
我代码:
#determine biggest word
words=("Hello" "World" "good" "etceter")
numchar=0
for i in ${words[@]}; do
if [ ${#i} -gt $numchar ]
then
numchar=${#i}
fi
done
#write *
a=-4
while [ $a -lt $numchar ]; do
printf "*"
((a++))
done
#write array
echo
for txt in ${words[@]}; do
space=$(($numchar-${#txt}))
s=0
echo "* $txt "
while [ $s -lt $space ]; do
printf " "
((s++))
printf "*"
done
done
#write *
a=-4
while [ $a -lt $numchar ]; do
printf "*"
((a++))
done
我正在努力与#写数组部分。
提前感谢!
你只需要做一些改动。
#write array
echo
for txt in ${words[@]}; do
space=$(($numchar-${#txt}))
s=0
echo -n "* $txt " # -n added to not append a newline
while [ $s -lt $space ]; do
echo -n " " # switched from printf to echo (cosmetics)
((s++))
# printf "*" # commented out
done
echo "*" # added
done
您的while
循环只在当前单词后面添加空格。末尾的*
在循环之后结束这一行。
改写后三段:
# define solid string of asterisks
printf -v stars '*%.0s' $(seq 1 $(( numchar + 4)) ) # length = numchar + 4
echo "${stars}"
for txt in "${words[@]}"
do
printf "* %-*s *n" "${numchar}" "${txt}"
done
echo "${stars}"
由此产生:
***********
* Hello *
* World *
* good *
* etceter *
***********
这是硬编码,但我想你已经明白了:
$ echo '***********'; printf '* %-8s*n' "${words[@]}"; echo '***********'
***********
* Hello *
* World *
* good *
* etceter *
***********
您首先获得最长行的长度是正确的。
边框和填充可以完全用printf
格式说明符和模式替换来完成。使用%-Ns
左对齐,%Ns
右对齐。
通过正确的引号,每行也可以有多个单词和空格。
下面是一个例子:
lines=('Hello World!'
'Line two.'
a-line
'another line'
'The end.')
# border character
c='*'
# get length of longest line, required for padding
for i in "${lines[@]}"; do
((${#i} > pad)) &&
pad=${#i}
done
# make a string to fill top/bottom
fill=$(printf %$((pad + 4))s "$c")
fill=${fill// /$c}
# print the text box
printf '%sn' "$fill"
for line in "${lines[@]}"; do
printf "$c %-${pad}s $cn" "$line"
done
printf '%sn' "$fill"
输出:
****************
* Hello World! *
* Line two. *
* a-line *
* another line *
* The end. *
****************