如何返回404当返回类型如果MappingJacksonValue从@RestController

Question

我有以下Spring @RestController方法:

public MappingJacksonValue getUserView(User viewer, Long vieweeid) {
User viewee = getUser(vieweeid);
if(viewee == null) throw new ResponseStatusException(
HttpStatus.NOT_FOUND, "entity not found"
);
final MappingJacksonValue result = new MappingJacksonValue(viewee);
Class view = Views.Minimal.class;
if(viewer.getId().equals(viewee.getId())) {
view = Views.Full.class;
}
...some lines omitted...
result.setSerializationView(view);
return result;
}

虽然这工作得很好，但如果没有找到请求的实体，我不高兴抛出一个异常来返回404。

处理这种情况的最佳实践是什么?

Answer 1

如果你愿意，你可以让你的方法返回ResponseEntity<MappingJacksonValue>，然后返回ResponseEntity.notFound().build():

public ResponseEntity<MappingJacksonValue> getUserView(User viewer, Long vieweeid) {
User viewee = getUser(vieweeid);
if(viewee == null) return ResponseEntity.notFound().build();
final MappingJacksonValue result = new MappingJacksonValue(viewee);
Class view = Views.Minimal.class;
if(viewer.getId().equals(viewee.getId())) {
view = Views.Full.class;
}
...some lines omitted...
result.setSerializationView(view);
return ResponseEntity.ok(result);
}