puppeteer-cluster，不同的数据到同一个url

Question

我在下面放了一个例子，我想在同一时间从对象数组添加不同的搜索输入(firstWord + scndWord)到两个google页面，因此打开页面动态取决于数组长度打开谷歌的第一页，然后写红花第二页打开谷歌，但写"游戏PC">

const { Cluster } = require('puppeteer-cluster');
(async () => {
const cluster = await Cluster.launch({
concurrency: Cluster.CONCURRENCY_PAGE,
maxConcurrency: 10,
puppeteerOptions: {
headless: false,
},

});
cluster.on('taskerror', (err, url) => {
console.error((new Date()).toJSON() + `  Error crawling ${url}: ${err.message}`);
});
const arr = [
{firstWord: 'gaming ',scndWord: 'pc'},
{firstWord: 'red ', scndWord: 'flower'}
]

await cluster.task(async ({ page, data: index }) => {
await page.goto('https://www.google.com/');
await page.focus('body > div.L3eUgb > div.o3j99.ikrT4e.om7nvf > form > div:nth-child(1) > div.A8SBwf > div.RNNXgb > div > div.a4bIc > input')
await page.keyboard.type('flower');
await page.waitForNavigation()
await page.screenshot({ path: 'screenshot.png', fullPage: true })
});
for (let index = 0; index <=arr.length -1 ; index++) {
cluster.execute(index);}

我不知道怎么做，我会感谢你的帮助

Answer 1

我明白了

const { Cluster } = require('puppeteer-cluster');

(async () => {
const cluster = await Cluster.launch({
concurrency: Cluster.CONCURRENCY_PAGE,
maxConcurrency: 10,
puppeteerOptions: {
headless: false,
},

});
cluster.on('taskerror', (err, url) => {
console.error((new Date()).toJSON() + `  Error crawling ${url}: ${err.message}`);
});
const arr = [
{firstWord: 'gaming ',scndWord: 'pc'},
{firstWord: 'red ', scndWord: 'flower'}
]

await cluster.task(async ({ page, data: [firstWord , scndWord] }) => {
await page.goto('https://www.google.com/');
await page.focus('body > div.L3eUgb > div.o3j99.ikrT4e.om7nvf > form > div:nth-child(1) > div.A8SBwf > div.RNNXgb > div > div.a4bIc > input')
await page.keyboard.type(firstWord + scndWord);
await page.waitForNavigation()
await page.screenshot({ path: 'screenshot.png', fullPage: true })
});

arr.map((serach)=>{
cluster.execute([serach.firstWord, serach.scndWord]);
})
//   await cluster.idle();
//   await cluster.close();
})();