如何比较两个zip文件完全相同或不相同的文件?

Question

我有两个zip文件。我想看看是否所有内容(文件名和每个文件的内容)都是相同的。

有一个类似的问题。但是答案不支持zip文件。

谁有好主意?

Answer 1

下面是我的尝试。只要确保ZipFiles包含相同的项并且这些项具有匹配的crc32就足够了。(比较两个ZipFiles具有相同名称和相同CRC32但不同文件的文件的机会是什么?)如果这样就足够了，可以省略比较文件内容的循环。

from zipfile import ZipFile
BUFSIZE = 1024
def are_equivalent(filename1, filename2):
"""Compare two ZipFiles to see if they would expand into the same directory structure
without actually extracting the files.
"""

with ZipFile(filename1, 'r') as zip1, ZipFile(filename2, 'r') as zip2:

# Index items in the ZipFiles by filename. For duplicate filenames, a later
# item in the ZipFile will overwrite an ealier item; just like a later file
# will overwrite an earlier file with the same name when extracting.
zipinfo1 = {info.filename:info for info in zip1.infolist()}
zipinfo2 = {info.filename:info for info in zip2.infolist()}

# Do some simple checks first
# Do the ZipFiles contain the same the files?
if zipinfo1.keys() != zipinfo2.keys():
return False

# Do the files in the archives have the same CRCs? (This is a 32-bit CRC of the
# uncompressed item. Is that good enough to confirm the files are the same?)
if any(zipinfo1[name].CRC != zipinfo2[name].CRC for name in zipinfo1.keys()):
return False

# Skip/omit this loop if matching names and CRCs is good enough.
# Open the corresponding files and compare them.
for name in zipinfo1.keys():

# 'ZipFile.open()' returns a ZipExtFile instance, which has a 'read()' method
# that accepts a max number of bytes to read. In contrast, 'ZipFile.read()' reads
# all the bytes at once.
with zip1.open(zipinfo1[name]) as file1, zip2.open(zipinfo2[name]) as file2:

while True:
buffer1 = file1.read(BUFSIZE)
buffer2 = file2.read(BUFSIZE)

if buffer1 != buffer2:
return False

if not buffer1:
break

return True

Answer 2

似乎zip将有不同的哈希，即使你压缩相同的项目。我们可以把它分成两部分:第一部分是解压缩，第二部分是比较解压缩后的文件夹。

import os
import filecmp
import zipfile
def are_dir_trees_equal(dir1, dir2):
dirs_cmp = filecmp.dircmp(dir1, dir2)
if len(dirs_cmp.left_only)>0 or len(dirs_cmp.right_only)>0 or 
len(dirs_cmp.funny_files)>0:
return False
(_, mismatch, errors) =  filecmp.cmpfiles(
dir1, dir2, dirs_cmp.common_files, shallow=False)
if len(mismatch)>0 or len(errors)>0:
return False
for common_dir in dirs_cmp.common_dirs:
new_dir1 = os.path.join(dir1, common_dir)
new_dir2 = os.path.join(dir2, common_dir)
if not are_dir_trees_equal(new_dir1, new_dir2):
return False
return True

BASE_PATH = '/Users/Documents/'
model1 = os.path.join(BASE_PATH, 'test1.zip')
model2 = os.path.join(BASE_PATH, 'test2.zip')
with zipfile.ZipFile(model1,"r") as zip_ref:
zip_ref.extractall(BASE_PATH)
with zipfile.ZipFile(model2,"r") as zip_ref:
zip_ref.extractall(BASE_PATH)
folder1 = model1.split('.')[0]
folder2 = model2.split('.')[0]
is_equal = are_dir_trees_equal(folder1, folder2)
print(is_equal)

Answer 3

我尝试在python中使用zipfile内置模块。

from zipfile import ZipFile
def compare(file1, file2):
try:
with ZipFile(file1, 'r') as file:
f1 = str([x for x in file.infolist()])
with ZipFile(file2, 'r') as file:
f2 = str([x for x in file.infolist()])
return f1 == f2
except FileNotFoundError:
return f"Either file at {file1} or {file2} does not exist"

f = compare(file1='storage/1.zip', file2='storage/2.zip')
print(f)

我不知道这是正确的方法或不(如果不是请纠正我)