Python字典:tuple作为键，tuple的列表作为值

Question

我在Python中有一个包含only one键值对的字典结构。键是一个元组，值是一个元组列表。示例:{(element1, element2): [(element1.1, element2.1), (element1.2, element2.2).....]}

我试图通过这个字典迭代，以获得关键，然后是值。然后我想构造另一个字典，它将包含:

{ element1: element2
element1.1: element2.1
element1.2: element2.2 }

我试过的是:

field_dictionary is the dictionary that I previously described.
for (k,v), l in field_dictionary:
log_dictionary[k] = v
for (element1, element2) in l:
log_dictionary[element1] = element2

我得到的是一个错误:

for (k,v), l in field_dictionary:
ValueError: too many values to unpack, expected 2

有人能帮我一下吗?

Answer 1

from itertools import chain
spam = {('element1', 'element2'): [('element1.1', 'element2.1'), ('element1.2', 'element2.2')]}
key, value = list(spam.items())[0]
eggs = dict(chain((key,), value))
print(eggs)

输出:

{'element1': 'element2', 'element1.1': 'element2.1', 'element1.2': 'element2.2'}

或者

for key, value in spam.items():
eggs = dict(chain((key, ), value))
print(eggs)

相同的输出