我有两个表
日历
FirstDate | LastDate
------------+-----------
2020-05-01 2020-05-03
2020-05-02 2020-05-04
ProfileRate
ID | Date | Rate | Product
---+------------+------+----------
1 2020-05-01 100 Prod1
2 2020-05-02 200 Prod1
3 2020-05-03 300 Prod1
4 2020-05-04 400 Prod1
5 2020-05-01 150 Prod2
6 2020-05-02 250 Prod2
7 2020-05-03 350 Prod2
8 2020-05-04 450 Prod2
我想计算SUM。像这样的
FirstDate | LastDate | Prod1 | Prod2
------------+-------------+--------+-------
2020-05-01 2020-05-03 600 750
2020-05-02 2020-05-04 900 1050
我尝试过的:
SELECT [Date], SUM([Rate])
FROM [ProfileRate]
WHERE [Date] BETWEEN '2020-05-01' AND '2020-05-04'
GROUP BY [Date]
请帮帮我。谢谢
您必须执行几个步骤来解决问题:
- 将日历记录与配置文件相结合
- 确定哪些配置文件符合日历范围
- 合计每个配置文件和日期范围的值
- 最终建立日历的详细信息
此查询满足条件
with DataForCalendar as
(
SELECT IdCalendar,FirstDate,LastDate,Id,DateRate,Rate,Product
FROM
Calendar CROSS JOIN ProfileRate
where DateRate between '2020-05-01' and '2020-05-05'
),
DetailForCalendar as
(
select IdCalendar,Rate,Product
from DataForCalendar
where DateRate between FirstDate and LastDate
),
TotalForCalendar as
(
select IdCalendar,Product,sum(Rate)As Total from DetailForCalendar
GROUP BY IdCalendar,Product
)
select Calendar.IdCalendar,Calendar.FirstDate,Calendar.LastDate,
TotalForCalendar.Product,TotalForCalendar.Total
from TotalForCalendar inner join
Calendar on TotalForCalendar.IdCalendar=Calendar.IdCalendar;
在这个例子中,你可以一步一步地找到它是如何工作的
在这个例子中,还有一个产品和一个日历。
我认为这是一个JOIN
和条件聚合:
SELECT c.FirstDate, c.LastDate,
SUM(CASE WHEN pr.prod = 'Prod1' THEN pr.Rate END) as prod1,
SUM(CASE WHEN pr.prod = 'Prod2' THEN pr.Rate END) as prod2
FROM Calender c LEFT JOIN
ProfileRate pr
ON pr.Date >= c.FirstDate AND pr.Date <= c.LastDate
GROUP BY c.FirstDate, c.LastDate;
执行联接&条件聚合:
select c.fisrtdate, c.lastdate,
sum(case when pr.product = 'prod1' then rate else 0 end) as prod1,
sum(case when pr.product = 'prod2' then rate else 0 end) as prod2
from calendar c join
ProfileRate pr
on pr.date >= c.fisrtdate and pr.date <= c.lastdate
group by c.fisrtdate, c.lastdate;
如果需要所有日历日期,请使用left
联接。