转换空白以返回某物

Question

我在c++中有这个void函数

void DrawFace(cv::Mat img, Window face)
{
int x1 = face.x;
int y1 = face.y;
int x2 = face.width + face.x - 1;
int y2 = face.width + face.y - 1;
int centerX = (x1 + x2) / 2;
int centerY = (y1 + y2) / 2;
std::vector<cv::Point> pointList;
pointList.push_back(RotatePoint(x1, y1, centerX, centerY, face.angle));
pointList.push_back(RotatePoint(x1, y2, centerX, centerY, face.angle));
pointList.push_back(RotatePoint(x2, y2, centerX, centerY, face.angle));
pointList.push_back(RotatePoint(x2, y1, centerX, centerY, face.angle));
DrawLine(img, pointList);
}

我想让它只返回pointList向量，我对其进行了更改

void Drawface(cv::Mat img, Window face) 
{
int x1 = face.x;
int y1 = face.y;
int x2 = face.width + face.x - 1;
int y2 = face.width + face.y - 1;
int centerX = (x1 + x2) / 2;
int centerY = (y1 + y2) / 2;
std::vector<cv::Point> pointList;
pointList.push_back(RotatePoint(x1, y1, centerX, centerY, face.angle));
pointList.push_back(RotatePoint(x1, y2, centerX, centerY, face.angle));
pointList.push_back(RotatePoint(x2, y2, centerX, centerY, face.angle));
pointList.push_back(RotatePoint(x2, y1, centerX, centerY, face.angle));
return pointList
}

如果有人能指出我哪里出了问题，以及我能做出什么改变，那将是非常有帮助的。

提前感谢

Answer 1

函数的返回类型仍然是void。你需要改变它来反映身体的变化。此外，return pointList后面缺少分号。

Answer 2

您需要声明函数的返回类型。

std::vector<cv::Point> Drawface(cv::Mat img, Window face) 
{
int x1 = face.x;
int y1 = face.y;
int x2 = face.width + face.x - 1;
int y2 = face.width + face.y - 1;
int centerX = (x1 + x2) / 2;
int centerY = (y1 + y2) / 2;
std::vector<cv::Point> pointList;
pointList.push_back(RotatePoint(x1, y1, centerX, centerY, face.angle));
pointList.push_back(RotatePoint(x1, y2, centerX, centerY, face.angle));
pointList.push_back(RotatePoint(x2, y2, centerX, centerY, face.angle));
pointList.push_back(RotatePoint(x2, y1, centerX, centerY, face.angle));
return pointList;
}