以npy/pickle格式保存和加载日期时间对象

Question

我正在尝试以分钟为单位计算两个时间戳之间的差异，如果差异大于阈值，我将执行任务。到目前为止，我已经尝试过做差异，但它给出了一个错误，因为日期时间差异没有给我任何数值。

我还需要将第一个日期时间对象保存为numpy数组/pickle，而不是数据库列，因为这对我的任务更方便。

import datetime
import time
a = datetime.datetime.now() # save this timestamp for later comparison
# save as numpy array
# load the array
time.sleep(100) # program closes, and re-opens
b = datetime.datetime.now()
# comparison in minutes
diff = b-a
# if diff > 60 minutes, do something
if diff > 60:
pass

我得到的错误：

---> 20 if diff > 60:
21   pass
22 
TypeError: '>' not supported between instances of 'datetime.timedelta' and 'int'

Answer 1

这是您更新的代码。

import datetime
import time
import numpy as np
a = datetime.datetime.now() # save this timestamp for later comparison
np_format = np.array([a.year, a.month, a.day, a.hour, a.minute, a.second, a.microsecond]) # all numeric values
np.save('date_old.npy', np_format)
a_load = np.load('date_old.npy')
a_loaded = datetime.datetime(a_load[0], a_load[1], a_load[2], a_load[3], a_load[4], a_load[5], a_load[6])
print(a)
print(a_loaded)
# save as numpy array
# load the array
time.sleep(100) # program closes, and re-opens
b = datetime.datetime.now()
# comparison in minutes
diff = (b-a_loaded).total_seconds()/60.
# if diff > 60 minutes, do something
print(diff)
if diff > 1:
print('hello')

输出：

2020-04-12 18:14:29.439318
2020-04-12 18:14:29.439318
1.6676882
hello