我有一个日期列。我想得到每个日期的财政季度年度与最大财政季度年度之间的差额。我就是这样做的:
date = pd.Series(['2019-01-01', '2019-03-01', '2019-07-01', '2020-03-01'])
date = pd.to_datetime(date)
year_quarter = pd.PeriodIndex(date, freq='Q-JAN')
max_year_quarter = year_quarter.max()
print(year_quarter)
print(max_year_quarter)
输出:
year_quarter
PeriodIndex(['2019Q4', '2020Q1', '2020Q2', '2021Q1'], dtype='period[Q-JAN]', freq='Q-JAN')
max_year_quarter
Period('2021Q1', 'Q-JAN')
如果我运行max_year_quarter - max_year_quarter
,输出将是:
Index([<5 * QuarterEnds: startingMonth=1>, <4 * QuarterEnds: startingMonth=1>,
<3 * QuarterEnds: startingMonth=1>, <0 * QuarterEnds: startingMonth=1>],
dtype='object')
而预期输出为:
[5, 4, 3, 0]
其是每个日期和max_year_quarter之间的季度数。我感谢你的帮助。
这将导致季度数:
Difference = max_year_quarter - year_quarter
Difference_in_Quarter = (max_year_quarter - year_quarter).map(lambda x: x.n)
输出:
0 5
1 4
2 3
3 0
dtype: int64
将Period.ordinal
用于整数repr,并通过将PeriodIndex
的值转换为整数进行减法:
Difference_in_Quarter = max_year_quarter.ordinal - year_quarter.astype(int)
print (Difference_in_Quarter)
Int64Index([5, 4, 3, 0], dtype='int64')