我一直在尝试创建一个简单的程序,将输入的数字划分为比索。我需要的输出是
Enter Amount: 7350
P1000: 7
P500: 0
P200: 1
P100: 1
P50: 1
P20:0
P10:0
P5:0
P1:0
这是我最初的代码:
#include <iostream>
using namespace std;
int main()
{
int const P1000(1000);
int const P500(500);
int const P200(200);
int const P100(100);
int const P50(50);
int const P20(20);
int const P10(10);
int const P1(1);
int input;
//input number
cout<<"input number in pesos: ";
cin>>input;
cout<<"P1000 = "<<input/P1000<<endl;
cout<<"P500 = "<<(input%1000)/P500<<endl;
cout<<"P200 = "<<(input%500)/P200<<endl;
cout<<"P100 = "<<(input%200)/P100<<endl;
cout<<"P50 = "<<(input%100)/P50<<endl;
cout<<"P20 = "<<(input%50)/P20<<endl;
cout<<"P10 = "<<(input%20)/P10<<endl;
cout<<"P1= "<<(input%10)/P1<<endl;
return 0;
}
但是我得到的输出是
input number in pesos: 7350
P1000 = 7
P500 = 0
P200 = 1
P100 = 1
P50 = 1
P20 = 0
P10 = 1
P1= 0
所以经过一点修改,我使用了这段代码,它产生了奇迹!
#include <iostream>
using namespace std;
int main()
{
int const P1000(1000);
int const P500(500);
int const P200(200);
int const P100(100);
int const P50(50);
int const P20(20);
int const P10(10);
int const P1(1);
int input;
//input number
cout<<"input number in pesos: ";
cin>>input;
cout<<"P1000 = "<<input/P1000<<endl;
cout<<"P500 = "<<(input%=1000)/P500<<endl;
cout<<"P200 = "<<(input%=500)/P200<<endl;
cout<<"P100 = "<<(input%=200)/P100<<endl;
cout<<"P50 = "<<(input%=100)/P50<<endl;
cout<<"P20 = "<<(input%=50)/P20<<endl;
cout<<"P10 = "<<(input%=20)/P10<<endl;
cout<<"P1= "<<(input%=10)/P1<<endl;
return 0;
}
所以我的问题是,为什么使用复合模运算符是如何工作的?它与常规的模运算符有何不同?我认为问题不在于数学,而在于代码的处理方式。这是我学习C++(以及一般编程(的头几周,如果能澄清一些困惑,那就太好了。提前谢谢。
这里有一个小程序来说明区别:
#include <iostream>
int main()
{
int i = 256;
std::cout << "i: " << i << ", i % 100: " << (i % 100) << std::endl;
std::cout << "i: " << i << ", i % 12: " << (i % 12) << std::endl;
std::cout << "i: " << i << ", i % 3: " << (i % 3) << std::endl;
std::cout << std::endl;
std::cout << "i: " << i << ", i %= 100: " << (i %= 100) << std::endl;
std::cout << "i: " << i << ", i %= 12: " << (i %= 12) << std::endl;
std::cout << "i: " << i << ", i %= 3: " << (i %= 3) << std::endl;
}
此输出(固定空间更好(:
i: 256, i % 100: 56
i: 256, i % 12: 4
i: 256, i % 3: 1
i: 256, i %= 100: 56
i: 56, i %= 12: 8
i: 8, i %= 3: 2
正如您在第一部分中看到的,正则模运算符将i
保留为原始值。这意味着我们得到256模100,12和3。
然而,在第二部分中,复合模运算符不断改变i
,使得下一个模只对余数进行运算。