如何从嵌套列表中的每个子列表中提取到倒数第二个元素?
x = [[1, 2, 3], [4, 5], [7, 8, 9], [1, 3, 5, 6, 8]]
所需输出为:
y = [[1, 2], [4], [7, 8], [1, 3, 5, 6]]
您可以使用以下方法来完成此操作:
x = [[1, 2, 3], [4, 5], [7, 8, 9], [1, 3, 5, 6, 8]]
y = [sublist[:-1] for sublist in x]
输出:
[[1, 2], [4], [7, 8], [1, 3, 5, 6]]
你可以试试这个:
y = [ar[:-1] for ar in x]