StringBuilder and Indentation

Question

我试图在StringBuilder中缩进字符串块，但我得到的只是第一行的缩进。我理解它为什么这么做，但不知道是否有什么简单的方法可以实现我想要的。

void Main()
{
var subLines = new StringBuilder();
subLines.AppendLine("Sub Line1");
subLines.AppendLine("Sub Line2");
subLines.AppendLine("Sub Line3");
var mainLines = new StringBuilder();
mainLines.AppendLine("Main Line 1");
mainLines.AppendLine("Main Line 2");    
mainLines.Append("t").Append(subLines.ToString());
mainLines.AppendLine("Main Line 3");
mainLines.ToString().Dump();
}

实际输出

Main Line 1
Main Line 2
Sub Line1
Sub Line2
Sub Line3
Main Line 3

预期输出

Main Line 1
Main Line 2
Sub Line1
Sub Line2
Sub Line3
Main Line 3

我也尝试过使用IndentedTextWriter，但得到了相同的结果。

public static class StringBuilderExtensions
{ 
public static StringBuilder AppendIndented(this StringBuilder sb, string text)
{
var textWriter = new StringWriter(sb);
var indentWriter = new IndentedTextWriter(textWriter, "tt");
indentWriter.WriteLine("");
indentWriter.Indent = 1;
indentWriter.WriteLine(text);
return sb;
}
}

关于如何实现块缩进，有什么想法吗？

Answer 1

根据canton7的评论，这里是我为实现结果而创建的扩展方法。

public static class StringBuilderExtensions
{
public static StringBuilder AppendIndented(this StringBuilder sb, string textBlock)
{
foreach (var line in textBlock.TrimEnd().Split('n'))
if (!string.IsNullOrWhiteSpace(line))
sb.AppendLine($"t{line}");
return sb;
}
}

用法

var subLines = new StringBuilder();
subLines.AppendLine("Sub Line1");
subLines.AppendLine("Sub Line2");
subLines.AppendLine("Sub Line3");
var mainLines = new StringBuilder();
mainLines.AppendLine("Main Line 1");
mainLines.AppendLine("Main Line 2");
mainLines.AppendIntended(sublines);
mainLines.AppendLine("Main Line 3");

Answer 2

这可能有助于

static void Main()
{
var subLines = new StringBuilder();
subLines.AppendLine("Sub Line1");
subLines.AppendLine("Sub Line2");
subLines.AppendLine("Sub Line3");
var mainLines = new StringBuilder();

ApplyIndentation(mainLines,subLines);

mainLines.ToString();
Console.WriteLine(mainLines);

}
private static void ApplyIndentation(StringBuilder mainLines, StringBuilder subLines)
{

string[] delim = { Environment.NewLine, "n" };
string[] lines = subLines.ToString().Split(delim, StringSplitOptions.None);
mainLines.AppendLine("Main Line 1");
mainLines.AppendLine("Main Line 2");
foreach (string line in lines)
{
mainLines.Append(Indent(3)).AppendLine(line);

}
mainLines.AppendLine("Main Line 3");
}
public static string Indent(int count)
{
return "".PadLeft(count);
}

Answer 3

您可以创建自己的StringBuilder实现，该实现与Debug的Debug方法相匹配。缩进((&调试。取消缩进((

public class StringBuilderIndented
{
private StringBuilder sb;
public string _Indent = "";
public StringBuilderIndented()
{
sb = new StringBuilder();
}
public void Indent()
{
_Indent += new string(' ', 5);
}
public void WriteLine(string str)
{
sb.AppendLine(_Indent+str);
}
public void Unindent()
{
if (_Indent.Length >= 5)
_Indent = new string(' ', _Indent.Length - 5);
else
_Indent = "";
}
public override string ToString()
{
return sb.ToString();
}
}

用法：

然后，在使用Debug进行编写的代码中，您可以将其替换为您的字符串生成器调用

private static void WriteLog()
{
var Debug = new StringBuilderIndented();
Debug.WriteLine("Main Line 1");
Debug.WriteLine("Main Line 2");
Debug.Indent();
Debug.WriteLine("Sub Line 1");
Debug.WriteLine("Sub Line 2");
Debug.Indent();
Debug.WriteLine("Sub Sub Line 1");
Debug.WriteLine("Sub Sub Line 2");
Debug.Unindent();
Debug.WriteLine("Sub Line 3");
Debug.Unindent();
Debug.WriteLine("Main Line 3");
Trace.WriteLine(Debug.ToString());
}

输出：

Main Line 1
Main Line 2
Sub Line 1
Sub Line 2
Sub Sub Line 1
Sub Sub Line 2
Sub Line 3
Main Line 3